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Art [367]
4 years ago
15

The cylinder below has a volume of 2,512 cubic cm and a height of 8 centimeters. What is the diameter of the cylinder? Use 3.14

for pi.
Mathematics
2 answers:
EastWind [94]4 years ago
4 0
Calculate the volume of a cylinder using the formula V = r2 × π × h. Begin by first finding the area of the circle at one end. Square the radius of the circle and multiply the result by "pi" (the symbol π), or approximately 3.14. Multiply this result by the cylinder's height to get its volume.
Natasha_Volkova [10]4 years ago
3 0

Answer:7

Step-by-step explanation:

777777

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Gabriel is signing up for a gym membership with a one-time fee to join and then a monthly fee to remain a member. The the monthl
seraphim [82]

Answer;

T=100+40c

Step-by-step explanation:

T is the total cost so everything has to add up to that. 100 is a flat cost, plus 40 dollars a month for however long you stay with that program.

5 0
3 years ago
A baseball is hit upward from a height of
jeyben [28]

Answer:

99

Step-by-step explanation:

4 0
3 years ago
Value of the derivative of g(x)=8-10Cosx at 'x=0' is?
VLD [36.1K]

Answer:

g'(0) = 0

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

  • Function Notation

<u>Pre-Calculus</u>

  • Unit Circle

<u>Calculus</u>

  • Derivatives
  • Derivative Notation
  • The derivative of a constant is equal to 0
  • Derivative Property: \frac{d}{dx} [cf(x)] = c \cdot f'(x)
  • Trig Derivative: \frac{d}{dx} [cos(x)] = -sin(x)

Step-by-step explanation:

<u>Step 1: Define</u>

g(x) = 8 - 10cos(x)

x = 0

<u>Step 2: Differentiate</u>

  1. Differentiate [Trig]:                    g'(x) = 0 - 10[-sin(x)]
  2. Simplify Derivative:                   g'(x) = 10sin(x)

<u>Step 3: Evaluate</u>

  1. Substitute in <em>x</em>:                    g'(0) = 10sin(0)
  2. Evaluate Trig:                      g'(0) = 10(0)
  3. Multiply:                               g'(0) = 0
3 0
3 years ago
Use Newton''s method to find the second and third approximation of a root of x^3 + x + 3= 0 starting with x1 = -1 as the initial
BARSIC [14]

9514 1404 393

Answer:

  see attachment

Step-by-step explanation:

The iterator for Newton's method gives the next approximation (x') as ...

  x' = x -g(x)/g'(x) . . . . . where g'(x) is the derivative of g(x)

We have defined g(x) = x^3+x+3, the function we want the zero of. We have defined the iteration function to be f(x).

__

<em>Additional comment</em>

Modern graphing calculators not only make the iteration trivially simple, they also give a first approximation good to 2 or 3 decimal places in many cases.

7 0
3 years ago
Bo is buying a board game that usually costs BBB dollars. The game is on sale, and the price has been reduced by 18\%18%18, perc
AleksAgata [21]

Answer:

.82B

Step-by-step explanation:

I'm hoping you're asking to reduce the price by 18% once, because I'm not sure if that's your question, but it would be .82B. Which is 82% of the original price.

7 0
4 years ago
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