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3 years ago

Change the fraction 7/12 to a decimal. Round your answer to the nearest thousandth. A. 1.714 B. 1.700 C. .600 D. .583

Mathematics

1 answer:

mrs_skeptik [129]3 years ago

4 0

Divide

7/12 = <span>.583

We get answer: </span><span>D. .583</span>

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Step-by-step explanation:

$800 x 3.75% =$3,000

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An isosceles triangle in which the two equal sides, labeled a, are longer than the base, labeled b. This isosceles triangle has

Bas_tet [7]

Hey there! I’m happy to help!

We see that the two equal sides are longer than the base. This means that our a will be larger than b. The problem says that one of the longer sides is 6.3. Since the two longer sides are equal, that means that both longer sides are 6.3 cm. Therefore, we can simply subtract these two from the perimeter to find the shorter side, which is the base.

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I hope that this helps!

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3 years ago

The CEO of a large corporation asks his Human Resource (HR) director to study absenteeism among its executive-level managers at

Fynjy0 [20]

Answer:

Following are the answer to this question:

Step-by-step explanation:

Given:

n = 30 is the sample size.

The mean $\bar X$ = 7.3 days.

The standard deviation = 6.2 days.

df = n-1

$= 30-1 \\ =29$

The importance level is $\alpha$ = 0.10

The table value is calculated with a function excel 2010:

$= tinv (\ probility, \ freedom \ level) \\= tinv (0.10,29) \\ =1.699127\\ = t_{al(2x-1)}= 1.699127$

The method for calculating the trust interval of 90 percent for the true population means is:

Formula:

$\bar X - t_{al 2,x-1} \frac{S}{\sqrt{n}} \leq \mu \leq \bar X+ t_{al 2,x-1} \frac{S}{\sqrt{n}}$

$=\bar X - t_{0.5, 29} \frac{6.2}{\sqrt{30}} \leq \mu \leq \bar X+ t_{0.5, 29} \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 \frac{6.2}{\sqrt{30}}\leq \mu \leq7.3 +1.699127 \frac{6.2}{\sqrt{30}}\\\\=7.3 -1.699127 (1.13196)\leq \mu \leq7.3 +1.699127 (1.13196) \\\\=5.37 \leq \mu \leq 9.22 \\$

It can rest assured that the true people needs that middle managers are unavailable from 5,37 to 9,23 during the years.

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3 years ago