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Mrac [35]
2 years ago
9

You are playing the Integer Game. Here are the cards in your hand. 4 Integer Game cards. 4, negative 8, negative 3, and 2. a. Wh

at is the current value of your hand? Question 2 b. What card(s) could you remove from your hand in order to increase your score? Select all that apply. 4 4 −8 negative 8 −3 negative 3 2 2 Question 3 c. In order to win the Integer Game, your hand needs to have a total value that is closest to 0 . Which card should you remove from your hand to get as close to 0 as possible? 4 4 -8 -8 -3 -3 2 2 Question 4 What is the new value of your hand?
Mathematics
1 answer:
forsale [732]2 years ago
5 0

Answer:

-5, -8 and-3, -3, -2

Step-by-step explanation:

4, -8, -3, 2.

2a.

I assume the "current value" means add up the cards in your hand

4-8-3+2= -5

2b.

You can remove negative number cards to increase score!

That would be -8 and -3 cards.

3c.

If you can only remove one card, and your current hand is -5, lets see..

by removing a card, you subtract its value, so

-5-4 = -9, thats not good

-5-(-8) = 3, thats kind of close to zero

-5-(-3) = -2, thats pretty close to zero!

-5-2 = -7, that's not good

The closest to zero we can get is by removing the -3 card, for which our hand will have the value -2.

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5) Two machines M1, M2 are used to manufacture resistors with a design
Basile [38]

Answer:

Since M1 has the higher probability of being in the desired range, we choose M1.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Two machines M1, M2 are used to manufacture resistors with a design specification of 1000 ohm with 10% tolerance.

So we need the machines to be within 1000 - 0.1*1000 = 900 ohms and 1000 + 0.1*1000 = 1100 ohms.

For each machine, we need to find the probabilty of the machine being in this range. We choose the one with the higher probability.

M1:

Resistors of M1 are found to follow normal distribution with mean 1050 ohm and standard deviation of 100 ohm. This means that \mu = 1050, \sigma = 100

The probability is the pvalue of Z when X = 1100 subtracted by the pvalue of Z when X = 900. So

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1050}{100}

Z = 0.5

Z = 0.5 has a pvalue of 0.6915.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1050}{100}

Z = -1.5

Z = -1.5 has a pvalue of 0.0668

0.6915 - 0.0668 = 0.6247.

M1 has a 62.47% probability of being in the desired range.

M2:

M2 are found to follow normal distribution with mean 1000 ohm and standard deviation of 120 ohm. This means that \mu = 1000, \sigma = 120

X = 1100

Z = \frac{X - \mu}{\sigma}

Z = \frac{1100 - 1000}{120}

Z = 0.83

Z = 0.83 has a pvalue of 0.7967.

X = 900

Z = \frac{X - \mu}{\sigma}

Z = \frac{900 - 1000}{120}

Z = -0.83

Z = -0.83 has a pvalue of 0.2033

0.7967 - 0.2033 = 0.5934

M2 has a 59.34% probability of being in the desired range.

Since M1 has the higher probability of being in the desired range, we choose M1.

8 0
3 years ago
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