Answer:
1.59 m/s²
Step-by-step explanation:
Acceleration = change in Velocity over time. Mathematically it is represented as Δv/Δt
Given values in the question:
- Final velocity 203.0 km/h which is equal to (203/3.6)m/s = 56.39 m/s
- distance 2000 m
- Initial velocity is 0 m/s
<em>To use the equation for acceleration time is needed.</em>
<em>velocity= distance/time</em>
(203/3.6) = 2000/time <em>mltiplying both sides by time</em>
(203/3.6) x time = 2000 <em>making time subject of the formula</em>
time = 2000/(203/3.6)
time = 35.47 seconds
Substituting into the acceleration equation
acceleration =Δv/Δt
=(56.39- 0)/35.47
= 56.39/35.47
=1.59 m/s²
N-10 because you want to take 10 away from n
Given:
The vertex of a quadratic function is (4,-7).
To find:
The equation of the quadratic function.
Solution:
The vertex form of a quadratic function is:
...(i)
Where a is a constant and (h,k) is vertex.
The vertex is at point (4,-7).
Putting h=4 and k=-7 in (i), we get


The required equation of the quadratic function is
where, a is a constant.
Putting a=1, we get

![[\because (a-b)^2=a^2-2ab+b^2]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28a-b%29%5E2%3Da%5E2-2ab%2Bb%5E2%5D)
Therefore, the required quadratic function is
.