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enyata [817]
3 years ago
14

What is 5/6÷2 can you please help me

Mathematics
1 answer:
marishachu [46]3 years ago
3 0

Question

what is 5/6÷2?

Answer:

<h2>0.41 or 5/12 (same value)</h2>

Step-by-step explanation:

5/6 : 2 =

0.83 : 2 =

0.41

Or

5/6 : 2 =

5/6 * 1/2 =

5/12





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Prove : Cos^4A+sin^4A=1/4(3+cos4A)
Talja [164]

Answer:

1 = (sin^2 A + cos^2 A)^2 = sin^4 A + cos^4 A + 2 sin^2 A cos^2 A

so

sin^4 A + cos^4 A

= 1 - 1/2 sin^2 2A

= 1 - 1/4 (1- cos 4A)

= 1/4 (3+cos 4A)

Step-by-step explanation:

hope I helped

4 0
3 years ago
What is the slope of the line that passes through the points (4, 2) and (−16,−10)? Write your answer in simplest form
Rufina [12.5K]

Step-by-step explanation:

slope = y2 - y1

__________

x2 - x1

slope = (-10 -2) / (-16 - 4)

slope = -12/-20

slope = 3/5

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3 years ago
Part A
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I think the answer is 36π square inches, hope that help MLG  M8
6 0
4 years ago
V divided by 4 minus 10 =5 what is v?
love history [14]
The answer is 60
because first you subtract 10 on both sides 
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7 0
3 years ago
Read 2 more answers
Suppose the ice Q scores in one region are normally distributed within a standard deviation of 13. Suppose also that exactly 51%
elena-14-01-66 [18.8K]

Answer:

z=-0.025

And if we solve for \mu we got

\mu=100 +0.025*13=100.325

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the scores of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu,13)  

Where \mu=? and \sigma=13

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

For this case we know these conditions:

P(X>100)=0.51   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.  

As we can see on the figure attached the z value that satisfy the condition with 0.49 of the area on the left and 0.51 of the area on the right it's z=-0.025. On this case P(Z<-0.025)=0.49 and P(z>-0.025)=0.51

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=-0.025

And if we solve for \mu we got

\mu=100 +0.025*13=100.325

8 0
3 years ago
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