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Alexeev081 [22]
3 years ago
9

Find the probability of drawing an ace and a king in either order

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
8 0

Answer:

I think it is 2/4=1/2

Step-by-step explanation:

Let K=king

A=ace

Then you could the pattern KA, AK

So I think it would be 2/4=1/2

If it helped you please give me brainliest

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Answer:

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If the volume of a sphere is 660 mm, what is the radius of the sphere, to the nearest tenth of a millimeter?
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Answer:

Radius= 5.4

Step-by-step explanation:

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What is the answer to 3/5 x 10/21 in simplest form???
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3 years ago
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math problem Just before a referendum on a school budget, a local newspaper polls 400 voters in an attempt to predict whether th
Readme [11.4K]

Answer:

The conditions necessary for the analysis are met.

The probability the newspaper’s sample will lead them to predict defeat is 0.7881

Step-by-step explanation:

We are given;

population proportion; μ = 52% = 0.52

Sample size;n = 400

The conditions are;

10% conditon: sample size is less than 10% of the population size

Success or failure condition; np = 400 x 0.52 = 208 and n(1 - p) = 400(1 - 0.52) = 192.

Both values are greater than 10

Randomization condition; we assume that the voters were randomly selected.

So the conditions are met.

Now, the standard deviation is gotten from;

σ = √((p(1 - p)/n)

where;

p is the population proportion

n is the sample size

σ is standard deviation

Thus;

σ = √((0.52(1 - 0.52)/400)

σ = √((0.52(0.48)/400)

σ = 0.025

Now to find the z-value, we'll use;

P(p^ > 0.5) = P(z > (x - μ)/σ)

Thus;

P(p^ > 0.5) = P(z > (0.5 - 0.52)/0.025)

This gives;

P(p^ > 0.5) = P(z > - 0.8)

This gives;

P(p^ > 0.5) = 1 - P(z < -0.8)

From the table attached we have a z value of 0.21186

Thus;

P(p^ > 0.5) = 1 - 0.21186 = 0.7881

Thus, the probability the newspaper’s sample will lead them to predict defeat is 0.7871

8 0
3 years ago
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Pls help pls ill mark brainliest
stellarik [79]

Answer:

Area/Circumference is the length of a circle!

Step-by-step explanation:

8 0
3 years ago
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