3 years ago

Please help me with these questions!! Legit answers only please!!!

Mathematics

1 answer:

zimovet [89]3 years ago

6 0

Answer:

Values of y are:

2 3 4

1 -1 -3

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Need help asap!!!!! thank you!!

NeX [460]

Answer:

1,2,20

take away 14 from 8 = 6

add 6 to 14 = 20

Hope I helped!

NOTE: MARK BRAINLIEST!!!! plz....

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3 years ago

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PLEASE ANSWER ASAP

Karo-lina-s [1.5K]

Answer: 9/29

Step-by-step explanation:

Add all songs up. 29

Add pop and rap songs up. 9

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3 years ago

Please help me guys!!!

sdas [7]

I can't see the whole problem

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3 years ago

PLEASE HELP WILL GIVE THANKS AND FIVE STARS IF RIGHT ANSWER

Vika [28.1K]

(x+4)^2 / 9 - (y+3)^2 / 16 = 1

a^2 = 16 and b^2 = 9

a = +4 and -4

b = +3 and -3

Center is (-4, -3)

Vertices is (-4 + a, -3) and (-4 - a, -3)

Vertices is (-1, -3) and (-7, -3)

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3 years ago

Calculate the area of triangle ABC with altitude CD, given A (6,0) B(1,5) C (2,0) and D (4,2)

Elina [12.6K]

So hmm check the picture below

the height or altitude is CD
and the base is AB

how long are those? well $\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
A&({{ 6}}\quad ,&{{ 0}})\quad 
% (c,d)
B&({{ 1}}\quad ,&{{ 5}})\\\\
C&({{ 2}}\quad ,&{{ 0}})\quad 
% (c,d)
D&({{ 4}}\quad ,&{{ 2}})
\end{array}\qquad 
% distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
AB=\sqrt{(1-6)^2+(5-0)^2}\qquad \qquad CD=\sqrt{(4-2)^2+(2-0)^2}$

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3 years ago

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