<span>Round this to the nearest hundred. 728
= 700</span>
MKL = 83, JKL = 127, JKM = 9x - 10 <em>given</em>
JKL + MKL = JKM <em>angle addition postulate</em>
127 + 83 = 9x - 10 <em>substitution</em>
210 = 9x - 10 <em>simplify (add like terms)</em>
220 = 9x <em>addition property of equality</em>
= x
<h3>E
xplanation:</h3>
Replace cos^2(θ) with 1-sin^2(θ), and cot(θ) with cos(θ)/sin(θ).
cos^2(θ)cot^2(θ) = cot^2(θ) - cos^2(θ)
(1 -sin^2(θ))cot^2(θ) = . . . . . replace cos^2 with 1-sin^2
cot^2(θ) -sin^2(θ)·cos^2(θ)/sin^2(θ) = . . . . . replace cot with cos/sin
cot^2(θ) -cos^2(θ) = cot^2(θ) -cos^2(θ) . . . as desired
Answer:
99
Step-by-step explanation:
U will do the one outside first
122+1-4(6)
=123-24
= 99
Answer:
y = -5/9x + 4.1
(try doing this yourself first with different points to make sure this is the right answer, because im to lazy to check myself but ill try checking D:)
Step-by-step explanation:
first you have to find the slope . to do this use the equation y2 - y1/ x2 - x1
so write as -2 - 3/ -7 - 2 is equal to -5/-9
so now write y = -5/9x + b
we must now find the y-intercept so substitute one of the points given. lets substitute 2,3 it looks easier. So it will look like 3 = -5/9(2) + b
3 = -5/9(2) + b
3 = -10/9 + b
b = 3 + 10/9
b = 4.111111
um just round to the tenth place
