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scoundrel [369]
3 years ago
6

Please help me with these questions!! Legit answers only please!!!

Mathematics
1 answer:
zimovet [89]3 years ago
6 0

Answer:

Values of y are:

2 3 4

1 -1 -3

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Need help asap!!!!! thank you!!
NeX [460]

Answer:

1,2,20

take away 14 from 8 = 6

add 6 to 14 = 20

Hope I helped!

NOTE: MARK BRAINLIEST!!!! plz....

3 0
3 years ago
Read 2 more answers
PLEASE ANSWER ASAP
Karo-lina-s [1.5K]

Answer: 9/29

Step-by-step explanation:

Add all songs up. 29

Add pop and rap songs up. 9

8 0
3 years ago
Please help me guys!!!
sdas [7]
I can't see the whole problem
3 0
3 years ago
PLEASE HELP WILL GIVE THANKS AND FIVE STARS IF RIGHT ANSWER
Vika [28.1K]

(x+4)^2 / 9 - (y+3)^2 / 16 = 1


a^2 = 16 and b^2 = 9

a = +4 and -4

b = +3 and -3


Center is (-4, -3)

Vertices is (-4 + a, -3) and (-4 - a, -3)

Vertices is (-1, -3) and (-7, -3)

8 0
3 years ago
Calculate the area of triangle ABC with altitude CD, given A (6,0) B(1,5) C (2,0) and D (4,2)
Elina [12.6K]
So hmm check the picture below

the height or altitude is CD
and the base is AB

how long are those? well \bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
A&({{ 6}}\quad ,&{{ 0}})\quad 
%  (c,d)
B&({{ 1}}\quad ,&{{ 5}})\\\\
C&({{ 2}}\quad ,&{{ 0}})\quad 
%  (c,d)
D&({{ 4}}\quad ,&{{ 2}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
AB=\sqrt{(1-6)^2+(5-0)^2}\qquad \qquad CD=\sqrt{(4-2)^2+(2-0)^2}

7 0
3 years ago
Read 2 more answers
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