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3 years ago

6

Alice is making balloon bunches from 6 red balloons and 15 blue balloons. She wants the same number of red balloons and the same

number of blue balloons in each bunch. What is the greatest number of balloon bunches that Alice can making all the balloons?

2 answers:

zvonat [6]3 years ago

6 0

Answer:

3 bunches

Step-by-step explanation:

We are given that Alice is making balloon bunches from 6 red balloons and 15 blue balloons.

She wants the same number of red balloons and the same number of blue balloons in each bunch.

We have to find the greatest number of balloon bunches that Alice can making from all the balloons.

We will find the HCF of 6 and 15

$6=2\times 3$

$15=3\times 5$

Common factor of 6 and 15 is 3.

Hence, HCF of 6 and 15=3

Therefore, Alice makes 3 bunches with 2 red balloons and 5 blue balloons.

anyanavicka [17]3 years ago

3 0

3 bunches of 2 balloons each

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In (x + 2) (3x + 1) = 3x^2 + ___ + 2, what should be the value of the middle term to complete the product?

zvonat [6]

Answer:

middle term = 7x

Step-by-step explanation:

in order to find the middle term, we will expand the bracket on the left hand side and compare the expressions on both sides.

(x + 2) (3x + 1) = 3x² + ___ + 2

let the unknown expression = y

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Expanding the bracket on the left hand side by multiplication:

x + 2( 3x + 1) = (x × 3x) + (x × 1) + (2 × 3x) + ( 2 × 1)

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Comparing with the expression on the right hand side:

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3 years ago

7^x=3^[x+4] solve x using logarithmic

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By taking advantage of the definition of <em>exponential</em> and <em>logarithmic</em> function and their inherent relationship we conclude that the solution is x = 4 · ㏒ 3/(㏒ 7 - ㏒ 3).

<h3>How to solve an exponential equation by logarithms</h3>

<em>Exponential</em> and <em>logarithmic</em> functions are <em>trascendental</em> functions, these are, functions that cannot be described <em>algebraically</em>. In addition, <em>logarithmic</em> functions are the <em>inverse</em> form of <em>exponential</em> functions. In this question we take advantage of this fact to solve a given expression:

7ˣ = 3ˣ⁺⁴ Given
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By taking advantage of the definition of <em>exponential</em> and <em>logarithmic</em> function and their inherent relationship we conclude that the solution is x = 4 · ㏒ 3/(㏒ 7 - ㏒ 3).

To learn more on logarithms: brainly.com/question/20785664

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2 years ago

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Anestetic [448]

Answer:

-a^2

A

Step-by-step explanation:

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2 years ago

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2 years ago

Please help me asap i will give brainiest and all my points

Alinara [238K]

Answer:

a. Not Divisible

b. Divisible

c. Divisible

d. Divisible

e. Divisible

Step-by-step explanation:

To find the divisibility we need to follow the PEMDAS rule and check if the total value can be divided by the selected numbers without returning a remainder.

Let's begin with a:

$16^{5}+215$ by 33

$1,048,576 + 215$

$1,048,791$

We now then divide the total amount with 33.

$\dfrac{1,048,576}{33}$

= 31,781.5454

We can see that the value has a decimal point indicating that the total value divided by 33 will return a remainder. So it is NOT Divisible by 33.

Now let's continue on with the others.

$51^{7}-51^{6}$ by 25

$897,410,677,851 - 17,596,287,801$

$879,814,390,050$

We now then divide the total amount with 25.

$\dfrac{879,814,390,050}{25}$

= 35,192,575,602

The total value did NOT return a decimal point, therefore making the equation true. $51^{7}-51^{6}$ IS divisible by 25.

Next on we have:

$5^{5}-5^{4} +5^{3}$ by 7

$3,125 - 625 + 125$

As we know in the PEMDAS rule, that addition comes first. In this situation we have to read the equation from left to right and solve which ever comes first.

$2,500 + 125$

$2,625$

We now then divide the total amount with 7.

$\dfrac{2,625}{7}$

= 375

The total value did NOT return a decimal point, therefore making the equation true. $5^{5}-5^{4} +5^{3}$ IS divisible by 7.

$7^6+7^5-7^4$ by 11

$117,649+16,807-2,401$

$134,456-2,401$

$132,055$

We now then divide the total amount with 11.

$\dfrac{132,055}{11}$

= 12,005

The total value did NOT return a decimal point, therefore making the equation true. $7^6+7^5-7^4$ IS divisible by 11.

Last but not the least:

$5^{23}-5^{21}$ by 24

$11,920,928,955,078,125-476,837,158,203,125$

$11,444,091,796,875,000$

We now then divide the total amount with 24.

$\dfrac{11,444,091,796,875,000}{24}$

= 476,837,158,203,125

The total value did NOT return a decimal point, therefore making the equation true. $5^{23}-5^{21}$ IS divisible by 24.

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3 years ago