Alice is making balloon bunches from 6 red balloons and 15 blue balloons. She wants the same number of red balloons and the same
2 answers:
Answer:
3 bunches
Step-by-step explanation:
We are given that Alice is making balloon bunches from 6 red balloons and 15 blue balloons.
She wants the same number of red balloons and the same number of blue balloons in each bunch.
We have to find the greatest number of balloon bunches that Alice can making from all the balloons.
We will find the HCF of 6 and 15
Common factor of 6 and 15 is 3.
Hence, HCF of 6 and 15=3
Therefore, Alice makes 3 bunches with 2 red balloons and 5 blue balloons.
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So the distance formula is . Using this, our equation is
and we can solve for it as such:
As we see with this radical, the sum that's under it is 15^2 + 8^2, or the third option.
Answer:
<h2>Any point on the purple region.</h2><em>Look at the picture.</em>
Step-by-step explanation:
<, > - dotted line
≤, ≥ - solid line
<, ≤ - shaded region below a line
>, ≥ - shaded region above a line
y = 3x
for x = 0 → y = 3(0) = 0 → (0, 0)
for x = 2 → y = 3(2) = 6 → (2, 6)
y < 3x - dotted line, shaded region below the line
y = 5 - it's a horizontal line passes througth points (x, 5) <em>/x - any real number/</em>
y < 5 - dotted line, shaded region below the line
