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attashe74 [19]
3 years ago
11

Can u please help me with this question?

Mathematics
1 answer:
Masteriza [31]3 years ago
3 0

Answer:

B)y=\frac{-2}{3}x-\frac{-13}{3}

Step-by-step explanation:

2x +3y = 5

    3y = -2x + 5

Divide both sides by 3

\frac{3y}{3}=\frac{-2x}{3}+\frac{5}{3}\\\\y =\frac{-2}{3}x+\frac{5}{3}

Parallel lines have same slope.

m = (-2/3) ; (-2 , -3)

y - y1 = m(x -x1)

y-[-3]=\frac{-2}{3}(x-[-2])\\\\y + 3 = \frac{-2}{3}(x +2)\\\\y + 3 =\frac{-2}{3}x + 2*\frac{-2}{3}\\\\y+3=\frac{-2}{3}x-\frac{4}{3}\\\\y=\frac{-2}{3}x-\frac{4}{3}-3\\\\y=\frac{-2}{3}x-\frac{4}{3}-\frac{3*3}{1*3}\\\\y=\frac{-2}{3}x-\frac{4}{3}-\frac{9}{3}\\\\y=\frac{-2}{3}x-\frac{-13}{3}

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Answer:

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Step-by-step explanation:

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A jar contains 8 large red marbles, 5 small red marbles, 9 large blue marbles, and 7 small blue marbles. If a marble is chosen a
Eddi Din [679]

Answer:

P(blue|small) > P(small|blue)

Step-by-step explanation:

P(blue|small):  7 / (5 + 7) = 7 / 12

P(small|blue): 7 / ( 9 + 7) = 7 / 16

7 / 12 > 7 / 16

4 0
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In​ 2005, there were 14,100 students at college​ A, with a projected enrollment increase of 1000 students per year. In the same​
Ede4ka [16]

Let A be college A and let B be College B

A= 14,100

Rule: 1 Year = +1,000 students

B= 34,350

Rule: -1250 per year

1st Answer: 2017

Notice: I didn't show the formula because I'm not %100 sure I'm kind of off so if this is incorrect I'm deeply sorry. I truly am. On the bright side, I think its correct.

4 0
3 years ago
The ball followed a path modelled by the equation h = −0.001! + 0.5 + 2.5 where h is the height of the ball in feet and is the h
Mama L [17]

The heights the balls hit a fence at 350 ft distance are 65 feet, 38 feet and 30 feet, respectively

<h3>Represent the distance-height relationship for each player’s ball as an equation, in a table and on a graph. </h3>

<u>Juan</u>

Juan's equation is given as:

h = -0.001d^2 + 0.5d + 2.5

h =

Set d to multiples of 50 from 0 to 400.

So, the table of values of Juan's function is:

d (ft)                   h(ft)

0                          2.5

50                        25

100                      42.5

150                        55

200                      62.5

250                        65

300                      62.5

350                        65

400                      42.5

See attachment for the graph of Juan's function

<u>Mark</u>

A quadratic function is represented as:

h = ad^2 + bd + c

Using the values on the table of values, we have:

c = 3 -- the constant value

So, the equation becomes

h = ad^2 + bd + 3

Using the two other values on the table of values, we have:

23 = a(50)^2 + b(50) + 3

38 = a(100)^2 + b(100) + 3

Using a graphing tool, we have:

a = -0.001

b = 0.45

So, Mark's equation is h(d) = -0.001d^2 + 0.45d + 3

See attachment for Mark's graph.

<u>Barry</u>

From the graph, we have the table of values of Barry's function to be:

d (ft)                   h(ft)

0                          2.5

50                        21

100                      35

150                       44

200                      48

250                       46

300                      41

350                       30

400                      14

450                      0

Using a graphing tool, we have the quadratic function to be:

y = -0.001x^2 +0.4x +2.5

<h3><u>The shortest and the greatest distance before hitting the ground</u></h3>

From the graphs, equations and tables, the distance travelled by the balls are:

Juan = 505 feet

Mark = 457 feet

Barry = 450 feet

This means that Juan's ball would travel the greatest distance while Barry's ball would travel the shortest.

<h3>The height the balls hit a fence at 350 ft distance</h3>

To do this, we set d = 350

From the graphs, equations and tables, the height at 350 ft by the balls are:

Juan = 65 feet

Mark = 38 feet

Barry = 30 feet

The above represents the height the balls hit the fence

Read more about quadratic functions at:

brainly.com/question/12446886

#SPJ1

4 0
2 years ago
What is the value of x in the diagram below?
otez555 [7]

The cosine of 30° is √3 / 2.

Since cosine is Adjacent over Hypotenuse, Hypotenuse = (2 / √3) * 9 = 18 / √3.

The cosine of 45° is √2 / 2.

Therefore, X = (2 / √2) * (18 / √3) = 36 / √6 = 18 / √1.5 = C

8 0
3 years ago
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