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attashe74 [19]
3 years ago
11

Can u please help me with this question?

Mathematics
1 answer:
Masteriza [31]3 years ago
3 0

Answer:

B)y=\frac{-2}{3}x-\frac{-13}{3}

Step-by-step explanation:

2x +3y = 5

    3y = -2x + 5

Divide both sides by 3

\frac{3y}{3}=\frac{-2x}{3}+\frac{5}{3}\\\\y =\frac{-2}{3}x+\frac{5}{3}

Parallel lines have same slope.

m = (-2/3) ; (-2 , -3)

y - y1 = m(x -x1)

y-[-3]=\frac{-2}{3}(x-[-2])\\\\y + 3 = \frac{-2}{3}(x +2)\\\\y + 3 =\frac{-2}{3}x + 2*\frac{-2}{3}\\\\y+3=\frac{-2}{3}x-\frac{4}{3}\\\\y=\frac{-2}{3}x-\frac{4}{3}-3\\\\y=\frac{-2}{3}x-\frac{4}{3}-\frac{3*3}{1*3}\\\\y=\frac{-2}{3}x-\frac{4}{3}-\frac{9}{3}\\\\y=\frac{-2}{3}x-\frac{-13}{3}

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1.
<span>{a, e, i, o}
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Well "A" is {2, 3}, but I'm guessing you meant A'. 
A' is all the numbers you don't see, which is
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4.
</span><span>Suppose U={1, 2, 3, 4, 5, 6, 7, 8} is the universal set and P={2,4, 6, 8}. What is P?
Again, "P" is just {2,4, 6, 8}, but P' is all the numbers you don't see, which are all prime numbers in this sequence:
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5.
</span><span>-4 < k + 3 < 8
subtract 3 from all sides
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</span>6b - 1 < -7
add both sides by 1
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divide both sides by 6
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now do the other problem
2b + 1 > 5
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answer: b < -1 or b > 2

<span>8.
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