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Ilya [14]
3 years ago
12

To pay you for mowing the lawn, your grandmother puts money in a bag. The bag has one $10 bill and four $1 bills. You get to dra

w out two bills. What is the theoretical probability of getting $11? What is the probability of getting $2? Explain
Mathematics
2 answers:
ExtremeBDS [4]3 years ago
8 0
P(11)=8/20   
p(2)=12/20
Nat2105 [25]3 years ago
7 0
2 out of five and 2 out of five
In the bag its a ten dollar bill you have a one in five chance of getting the ten dollar bill
You have four ones in the bag you have a 4 in 5 chance of getting the one dollar bill.
Now to get 11 dollars you have a 2 in 5 chance because there is only 1 of the ten and 4 of the 1s
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QUICKLY HELP!
Leviafan [203]

a+(−5)=−12

a−5=−12

a = -12 + 5

a = -7

answer is b. a=−7

7 0
3 years ago
Read 2 more answers
What is the value of x in the proportion below? 8/72 = x/36
barxatty [35]

Answer:

x = 4

Step-by-step explanation:

8/72 = x/36

crossmultiply

8 x 36 = X x 72

288 = 72x

divide both sides by 72

288/72 = x

therefore , x = 4

3 0
3 years ago
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What is the area of this triangle?
grin007 [14]

Answer:

plz mark brainiest✌️✌️

3 0
3 years ago
Given the graph below, which of the following represents the domain of the function?
krek1111 [17]
Do you have the graph?
7 0
3 years ago
During the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this
alex41 [277]

Answer:

Step-by-step explanation:

Given that during  the period from 1790 to 1930, the US population P(t) (t in years) grew from 3.9 million to 123.2 million. Throughout this period, P(t) remained close to the solution of the initial value problem.

\frac{dP}{dt} =0.03135P =0.0001489P^2, P(0) = 3.9

a) 1930 population is the population at time t = 40 years taking base year as 40

We can solve the differential equation using separation of variables

\frac{dP}{0.03135P – 0.0001489P^2 } =dt\\\frac{dP}{-P(0.03135 – 0.0001489P } =dt

Resolve into partial fractions

\frac{31.8979}{P} -\frac{0.00474}{0.0001489P-0.03135}

Integrate to get

ln P -0.00474/0.0001489  (ln (0.0001489P-0.03135) = t+C

ln P -31.833  (ln (0.0001489P-0.03135) =t+C

\frac{P}{( ( (0.0001489P-0.03135)^{31.833}  } =Ae^t

Limiting population would be infinity.

6 0
3 years ago
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