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Ilya [14]
3 years ago
12

To pay you for mowing the lawn, your grandmother puts money in a bag. The bag has one $10 bill and four $1 bills. You get to dra

w out two bills. What is the theoretical probability of getting $11? What is the probability of getting $2? Explain
Mathematics
2 answers:
ExtremeBDS [4]3 years ago
8 0
P(11)=8/20   
p(2)=12/20
Nat2105 [25]3 years ago
7 0
2 out of five and 2 out of five
In the bag its a ten dollar bill you have a one in five chance of getting the ten dollar bill
You have four ones in the bag you have a 4 in 5 chance of getting the one dollar bill.
Now to get 11 dollars you have a 2 in 5 chance because there is only 1 of the ten and 4 of the 1s
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<img src="https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B9%7D%20" id="TexFormula1" title=" \sqrt[3]{9} " alt=" \sqrt[3]{9} " align=
Art [367]

Answer:

\sqrt[3]{9}= 2.08008...

Step-by-step explanation:

I used a calculator but 9 is not a perfect cube

7 0
3 years ago
A random sample of 20 purchases showed the sample mean of $48.77 and the sample standard deviation s is $17.58. How large is the
laila [671]

Answer:

<h2>$5.03</h2>

Step-by-step explanation:

Given data          

Sample Mean (M):  $48.77  

Sample Size (n): 20

Standard Deviation (σ) :  $17.58

Confidence Level: 80%

 we know that z*-Values for 80% Confidence  Levels is 1.28

the expression for margin of error is given bellow\

MOE= z*σ/√n

We can now substitute into the expression and solve for the MOE as

MOE= 1.28*17.58/√20

MOE= 22.502/4.47

MOE= 22.502/4.47

MOE= 5.03

The margin of error for a 80 % confidence interval is $5.03

3 0
3 years ago
How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?
Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = \dfrac{90000}{3}=30000

n( divisible by 5) = \dfrac{90000}{5}=18000

n( divisible by 7) = \dfrac{90000}{7}=12857.14

n( divisible by 3 and 5) = n(3∩5)=\dfrac{90000}{15}=6000

n( divisible by 5 and 7) = n(5∩7) = \dfrac{90000}{35}=2571.42

n( divisible by 3 and 7) = n(3∩7) = \dfrac{90000}{21}=4285.71

n( divisible by 3,5 and 7) = n(3∩5∩7) = \dfrac{90000}{105}=857.14

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

5 0
3 years ago
A bag contains 5 green marbles and 8 blue marbles. A dice is rolled, then a marble is chosen at random from the bag .
kolezko [41]
What is the question?
3 0
3 years ago
PLZ!!!
Len [333]

Answer:

16

Step-by-step explanation:

count each dot

5 0
2 years ago
Read 2 more answers
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