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3 years ago

12

Change 4 7/8 to an improper fraction ?

1 answer:

alex41 [277]3 years ago

8 0

Multiply 4&8, that makes 32 then add the numerator which is 7. 32+7=39, the improper fraction is 39/8. Hope this helps. If you need more info look online

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Find in degrees the numeric value of the acute angle of rotation that eliminates the product term from the equation 7x2+24xy−34x

lutik1710 [3]

Rotating the graph of $Ax^2+Bxy+Cy^2+Dx+Ey+F=0$ with $B\ne0$ counterclockwise by $\theta$ eliminates the $xy$ term, where $\cot2\theta=\frac{A-C}{B}.$ Plugging in, we have $\cot2\theta=\frac{7}{24},$ since $C=0.$ Solving, we have $\theta=\frac{1}{2}\cot^{-1}(\frac{7}{24})\approx\boxed{36.9^\circ}.$

4 0

3 years ago

I can't seem to answer this question may you guys help me

lina2011 [118]

Options A, B and E are the correct options.

Expenses are represented with negatives and income by positive.
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3 0

3 years ago

12-2²·2=?<br><br> Brainliest

zloy xaker [14]

Answer:

it would be 4

12-4×2=12-8=4

Step-by-step explanation:

hope it helps you

4 0

3 years ago

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I camper attaches a rope from the top of her tent 4 feet above the ground to give it more support if the Rope is 8 ft long about

iVinArrow [24]

Answer:

b = 6.928

Step-by-step explanation:

Looks like a job for the Pythagorean Theorem.

a^2 + b^2 = c^2

4^2 + b^2 = 8^2

16 + b^2 = 64

b^2 = 48

b = 6.928

Hope it helps!!

6 0

4 years ago

Jada was using square stickers that were 3/4in long to decorate the spine of a photo album. The spine is 10 and 1/2in long. If s

nevsk [136]

Answer:

13

Step-by-step explanation:

Given:

Square stickers that were 3/4 in long
The spine is 10 and 1/2 in long

If she laid the stickers side by side without gaps or overlaps so the number of sticker to cover the length of the spine:

$\frac{The length of the spine}{the length of the sticker}$

10 : $\frac{3}{4}$ ≈13

She needs 13 stickers cover the length of the spine

7 0

4 years ago

Read 2 more answers