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SashulF [63]
3 years ago
7

It costs $3.45 to buy 5/8 lb of chopped walnuts. How much would it cost to purchase 7.5 lbs of walnuts? Explain or show your

Mathematics
1 answer:
arsen [322]3 years ago
6 0
Poopyyyyyyyyyyyyyyyyyyyyy
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During the regular season, a National Basketball Association team plays 82 games and a National Football League team plays 16 ga
Naddika [18.5K]

Answer:

NFL teams play 16 regular season games each year, NHL and NBA teams play 82, while MLB teams play 162-could invalidate direct comparisons of win percentages alone. As an example, the highest annual team winning percentage is roughly 87% in the NFL but only 61% in MLB and part (but not all) of that difference is undoubtedly tied to the shorter NFL regular season

5 0
3 years ago
Help fast plss i have 0 brain cells to do this
Maslowich
The answer is the third one
6 0
3 years ago
Read 2 more answers
Pls help if you actually can
Setler79 [48]

The triangles that are similar would be ΔGCB and ΔPEB  due to Angle, Angle, Angle similarity theorem.

<h3>How to identify similar triangles?</h3>

From the image attached, we see that we are given the Parallelogram GRPC. Thus;

A.  The triangles that are similar would be ΔGCB and ΔPEB  due to Angle, Angle, Angle similarity theorem.

B. The proof of the fact that ΔGCB and ΔPEB are similar pairs of triangles is as follow;

∠CGB ≅ ∠PEB  (Alternate Interior Angles)

∠BPE ≅ ∠BCG  (Alternate Interior Angles)

∠GBC ≅ ∠EBP  (Vertical Angles)

C.  To find the distance from B to E and from P to E, we will first find PE and then BE by proportion;

225/325 = PE/375  

PE = 260 ft

BE/425 = 225/325  

BE = 294 ft

Read more about Similar Triangles at; brainly.com/question/14285697

#SPJ1

5 0
2 years ago
Please someone what is the total surface area of this pryamid ​
Dimas [21]

Answer:

\large\boxed{C.\ (25+25\sqrt3)\ in^2}

Step-by-step explanation:

We have the square and four equilateral triangles.

The formula of an area of a squre:

A_S=a^2

a - length of side

The formula of an area of an equilateral triangle:

A_T=\dfrac{a^2\sqrt3}{4}

a - length of side

Clculate the areas:

SQURE:

A_S=x^2\ in^2

TRIANGLE:

A_T=\dfrac{x^2\sqrt3}{4}\ in^2

The SURFACE AREA of a square pyramid:

S.A.=A_S+4A_T\\\\S.A.=x^2+4\cdot\dfrac{x^2\sqrt3}{4}=x^2+x^2\sqrt3

Put x = 5:

S.A.=5^2+5^2\sqrt3=(25+25\sqrt3)\ in^2

7 0
3 years ago
Please help with this math problem! :)
miskamm [114]

Answer:

Step-by-step explanation:

Diagonals intersect at 90

2z - 8 = 90

    2z  = 90 + 8

  2z = 98

    z = 98/2

z = 49

Adjacent sides are congruent

5x - 12 = 3x + 2

5x  = 3x + 2 + 12

5x = 3x + 14

5x - 3x = 14

2x = 14

x = 14/2

x = 7

3x + 2 = 3*7 + 2

          = 21 + 2

          = 23

Use Pythagorean theorem to find y

16² + y² = 23³

256 + y² = 529

          y² = 529 - 256 = 273

          y = √273

         y = 16.52

8 0
3 years ago
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