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SashulF [63]
3 years ago
7

It costs $3.45 to buy 5/8 lb of chopped walnuts. How much would it cost to purchase 7.5 lbs of walnuts? Explain or show your

Mathematics
1 answer:
arsen [322]3 years ago
6 0
Poopyyyyyyyyyyyyyyyyyyyyy
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Which statement correctly describes the relationship between the graph of f(x) and g(x)=f(x−7)?
anzhelika [568]

Step-by-step explanation:

When the number is inside the parenthesis. It means horizontal shift. Now negative is to the right and positive is to the left. Since it is negative 7 it would be 7 units to the right

any more help just ask :)

3 0
3 years ago
Read 2 more answers
1) The first triangle is dilated to form the second triangle. What is the scale factor? Please show your math work step by step.
Olin [163]

Answer:

2.5

Step-by-step explanation:

4/10 = 2.5 so the bigger triangle is 2.5 times bigger than the smaller one

7 0
3 years ago
The formula for the area A of a rectangle with a length of 5 inches is A = 5w, where w is the
Varvara68 [4.7K]

Answer:

Width 2 4 6 8

Area 10 20 30 40

Step-by-step explanation:

Area of a rectangle = length × width

Calculate width when length = 5 inches

When length = 5 inches and width = 2 inches

Area of a rectangle = length × width

A = 5 × 2

= 10 square inches

When length = 5 inches and width = 4 inches

Area of a rectangle = length × width

A = 5 × 4

= 20 square inches

When length = 5 inches and width = 6 inches

Area of a rectangle = length × width

A = 5 × 6

= 30 square inches

When length = 5 inches and width = 8 inches

Area of a rectangle = length × width

A = 5 × 8

= 40 square inches

Given the same length and different width

Width 2 4 6 8

Area 10 20 30 40

8 0
3 years ago
Please help me Asap
Schach [20]

Answer:

3

Step-by-step explanation:

5/9 - 3/8 - 1/4 + 1 4/9 + 1 5/8 = 3

hope this helps!

7 0
4 years ago
Read 2 more answers
Determine whether the series is convergent or divergent. 1 2 3 4 1 8 3 16 1 32 3 64 convergent divergent Correct:
Vanyuwa [196]

Answer:

This series diverges.

Step-by-step explanation:

In order for the series to converge, i.e. \lim_{n \to \infty} a_n =A it must hold that for any small \epsilon>0, there must exist n_0\in \mathbb{N} so that starting from that term of the series all of the following terms satisfy that  |a_n-A|n_0 .

It is obvious that this cannot hold in our case because we have three sub-series of this observed series. One of them is a constant series with a_n=1 , the other is constant with a_n=3 , and the third one has terms that are approaching infinity.

Really, we can write this series like this:

a_n=\begin{cases} 1 \ , \ n=4k+1, k\in \mathbb{N}_0\\ 2^{k}\ , \ n=2k, k\in \mathbb{N}_0\\3\ , \ n=4k+3, k\in \mathbb{N}_0\end{cases}

If we  denote the first series as b_n=1, we will have that \lim_{k \to \infty} b_k=1.

The second series is denoted as c_k=2^k and we have that \lim_{k \to \infty} c_k=+\infty.

The third sub-series d_k=3 is a constant series and it holds that \lim_{k \to \infty} d_k=3.

Since those limits of sub-series are different, we can never find such n_0\\ so that every next term of the entire series is close to one number.

To make an example, if we observe the first sub-series if follows that A must be equal to 1. But if we chose \epsilon =1, all those terms associated with the third sub-series will be out of this interval (A-1, A+1)=(0, 2).

Therefore, the observed series diverges.

5 0
4 years ago
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