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damaskus [11]
4 years ago
11

Calculate the final displacement from 0 if an object first

Mathematics
1 answer:
8_murik_8 [283]4 years ago
6 0

Answer:

final displacement = - 3cm +5cm = + 2 cm

ie 2 cm towards right

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Juli2301 [7.4K]

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3 years ago
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Use the long division method to find the result when x^3+7x^2+12x+6x 3 +7x 2 +12x+6 is divided by x+1x+1. If there is a remainde
Aliun [14]

Answer:

By long division (x³ + 7·x² + 12·x + 6) ÷ (x + 1) gives the expression;

x^2 + 5 \cdot x + 7 - \dfrac{1}{(x + 1)}

Step-by-step explanation:

The polynomial that is to be divided by long division is x³ + 7·x² + 12·x + 6

The polynomial that divides the given polynomial is x + 1

Therefore, we have;

\ \ \ \ \ \  \ \ \ \ \ \ x^2 + 5\cdot x + 7\\ (x + 1) \sqrt{x^3 + 7\cdot x^2 +12\cdot x + 6} \\\ {} \  {} \ {}  \  \ {} \  {} \ {}  \ {} \  {} \ {}   \ {}     \ \ x^3 + 2 \cdot x^2 \\\  \ \ \ {} \   \ {} \  {} \ {}   \  \ {} \ {} \  \   \ {} \  {} \ {}  \  \ {} \  {} \ {}  \ \ 5 \cdot x^2 + 12\cdot x + 6\\  \ {} \  {} \ {}    \ {} \  {} \ {}  \ \ {} \ {} 5 \cdot x^2 + 5\cdot x\\\ 7\cdot x+6\\7\cdot x+7\\-1

(x³ + 7·x² + 12·x + 6) ÷ (x + 1) = x² + 5·x + 7 Remainder -1

Expressing the result in the form q(x) + \dfrac{r(x)}{b(x)}, we have;

(x^3 + 7\cdot x^2 + 12 \cdot x + 6)\div (x + 1) =  x^2 + 5 \cdot x + 7 - \dfrac{1}{(x + 1)}

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Step-by-step explanation:

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Yeskcpowp kecksowofi h wncksorigud meocosuebd wkxos
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