Calculate the final displacement from 0 if an object first

Perform the multiplication. Simplify the answers. 2 √30*( √5+ √6+ √10+ √15)

Delicious77 [7]

The simplified expression of $2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15})$ is $10\sqrt{6} + 6\sqrt{20}+ 20\sqrt{3} + 30\sqrt{2}$

The expression is given as:

$2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15})$

Expand the expression

$2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2\sqrt{30} \times \sqrt5+ 2\sqrt{30} \times \sqrt6+ 2\sqrt{30} \times \sqrt{10} + 2\sqrt{30} \times \sqrt{15}$

Factor out 2

$2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2(\sqrt{30} \times \sqrt5+ \sqrt{30} \times \sqrt6+ \sqrt{30} \times \sqrt{10} + \sqrt{30} \times \sqrt{15})$

Combine the radicals

$2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2(\sqrt{150} + \sqrt{180}+ \sqrt{300} + \sqrt{450})$

Expand the expression

$2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2(\sqrt{25 \times 6} + \sqrt{9 \times 20}+ \sqrt{100 \times 3} + \sqrt{225\times 2})$

Evaluate the roots

$2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) = 2(5\sqrt{6} + 3\sqrt{20}+ 10\sqrt{3} + 15 \sqrt{2})$

Expand

$2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15}) =10\sqrt{6} + 6\sqrt{20}+ 20\sqrt{3} + 30\sqrt{2}$

Hence, the simplified expression of $2\sqrt{30} \times (\sqrt5+ \sqrt6+ \sqrt{10} + \sqrt{15})$ is $10\sqrt{6} + 6\sqrt{20}+ 20\sqrt{3} + 30\sqrt{2}$

Read more about simplified expressions at:

brainly.com/question/8008182

3 0

2 years ago

Please answer the question

shusha [124]

The answer should be C. 3

6 0

3 years ago

For each shape, write an algebraic expression for its perimeter - part A and B

nikitadnepr [17]

Answer:

a) p + q + r

b) 2(a + b)

Step-by-step explanation:

The perimeter of a two-dimensional shape is the distance all the way around the outside.

An algebraic expression contains one or more numbers, variables, and arithmetic operations.

A variable is a symbol (usually a letter) that represents an unknown numerical value in an equation or expression.

Question (a)

The length of each side of the triangle is labeled p, q and r. Therefore, the perimeter is the sum of the sides:

Perimeter = p + q + r

So the algebraic expression for the perimeter of the triangle is:

p + q + r

Question (b)

Not all of the sides of the shape have been labeled.

However, note that the horizontal length labeled "a" is equal to the sum of "c" and the horizontal length with no label.

Similarly, note that the vertical length labeled "b" is equal to the sum of "d" and the vertical length with no label.

Therefore, the perimeter is twice the sum of a and b:

Perimeter = 2(a + b)

So the algebraic expression for the perimeter of the shape is:

2(a + b)

5 0

1 year ago

Does the function satisfy the hypotheses of the Mean Value Theorem on the given interval? f(x) = 3x2 − 2x + 1, [0, 2] Yes, it do

expeople1 [14]

Answer:

Yes , function is continuous in [0,2] and is differentiable (0,2) since polynomial function are continuous and differentiable

Step-by-step explanation:

We are given the Function

f(x) = $3x^2 -2x +1$

The two basic hypothesis of the mean valued theorem are

The function should be continuous in [0,2]

The function should be differentiable in (1,2)

upon checking the condition stated above on the given function

f(x) is continuous in the interval [0,2] as the functions is quadratic and we can conclude that from its graph

also the f(x) is differentiable in (0,2)

f'(x) = 6x - 2

Now the function satisfies both the conditions

so applying MVT

6x-2 = f(2) - f(0) / 2-0

6x-2 = 9 - 1 /2

6x-2 = 4

6x=6

x=1

so this is the tangent line for this given function.

4 0

2 years ago

How would you solve that problem

antiseptic1488 [7]

Since you that that line is 180 degrees you can simply do 180-149 and find that the answer is 31 degrees. So you would do 13x+5=31, 31-5=26, 26/13, and then x=2 :)

7 0

3 years ago