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Tresset [83]
2 years ago
7

The functions f and g are defined by these sets if input and output values.

Mathematics
1 answer:
erastovalidia [21]2 years ago
5 0
(x,y)
x=input
y=output
example
we see
g=(1,2)
theefor
g(1)=2


a.
f(4)=1
g(1)=2
g(f(4))=2

b.
g(-2)=4
f(4)=1
f(g(-2))=1

c.
f(3)=5
g(5)=5
f(5)=0
f(g(f(3)))=0
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You purchase 2 action figures per week. You have 48 action figures, which is 75% of the total number of action figures you need
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Answer:

Step-by-step explanation:

Let the total number of action figures = x

75% of x = 48

\dfrac{75}{100}*x=48\\\\Multiply \ by \ 100\\\\75*x =48*100\\\\Divide  \ by \ 75\\\\x=\dfrac{48*100}{75}\\\\\\x=16*4\\\\x= 64

Remaining action figures need to be collected = total figures - number of action figures I have

= 64 - 48 = 16

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It will take 8 weeks to collect 16 action figures.

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2 years ago
Write 7,000+600+10+2 in standard form
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6,612 is the answer because all you need to do is combine them by their place value.
8 0
3 years ago
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Solve the system of linear equations below y=-2x+19 y=x+7
Julli [10]
<span>A) y=-2x+19
B) y=x+7 Multiplying B) by -1
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3 years ago
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An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 37 type K batteries and a sample of 58
Olegator [25]

Answer:

Hypothesis Test states that we will accept null hypothesis.

Step-by-step explanation:

We are given that an engineer is comparing voltages for two types of batteries (K and Q).

where, \mu_1 = true mean voltage for type K batteries.

           \mu_2 = true mean voltage for type Q batteries.

So, Null Hypothesis, H_0 :  \mu_1 = \mu_2 {mean voltage for these two types of

                                                        batteries is same}

Alternate Hypothesis, H_1 : \mu_1 \neq \mu_2 {mean voltage for these two types of

                                                          batteries is different]

<em>The test statistics we use here will be :</em>

                     \frac{(X_1bar-X_2bar) - (\mu_1 - \mu_2) }{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } }  follows t_n__1 + n_2  -2

where, X_1bar = 8.54         and     X_2bar = 8.69

                s_1  = 0.225       and         s_2     =  0.725

               n_1   =  37           and         n_2     =  58

               s_p = \sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2} } =   \sqrt{\frac{(37-1)0.225^{2}+(58-1)0.725^{2}  }{37+58-2} }  =  0.585               Here, we use t test statistics because we know nothing about population standard deviations.

     Test statistics =  \frac{(8.54-8.69) - 0 }{0.585\sqrt{\frac{1}{37}+\frac{1}{58}  } } follows t_9_3

                             = -1.219

<em>At 0.1 or 10% level of significance t table gives a critical value between (-1.671,-1.658) to (1.671,1.658) at 93 degree of freedom. Since our test statistics is more than the critical table value of t as -1.219 > (-1.671,-1.658) so we have insufficient evidence to reject null hypothesis.</em>

Therefore, we conclude that mean voltage for these two types of batteries is same.

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2 years ago
1. A bakery packages 96 boxes of muffins today. The bakery sells 4 sizes of boxes of muffins. The table shows how many muffins a
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Answer:1000

Step-by-step explanation:

Yes

8 0
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