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3 years ago

I will mark brainliest

Mathematics

2 answers:

Anna35 [415]3 years ago

8 0

It is D, none of the above!

BARSIC [14]3 years ago

6 0

Answer:

Your answer would be D, the last one

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John wants to join a gym so that he can work out during the evenings. There are two gyms in his town that he is considering. Ext

Y_Kistochka [10]

Answer:

It would be 4 months because with extreme fitness 10x4=40 then 40+50=90 then for ultimate fitness 15x4=60 then 60+30=90 so I took 4 months for both memberships to be the same

Step-by-step explanation:

Look at the answer above

3 0

3 years ago

Read 2 more answers

Find all real zeros of t<br>f(x)=x-14x² + 47x-18

BabaBlast [244]

Answer:

x=3/7 and x= 3

Step-by-step explanation:

First simplify:

-14 x^2 +48x -18

divide everything by -2

-2(7 x^2 -24x +9) (Multiply the leading coefficient 7 by the constant 9)

-2 (x^2 -24x +63)

-2 [(x-3)(x-21)] Now divide the 7 that you multiplied earlier from 3 and 21

-2 [(x-3/7)(x-21/7)]

-2 [(7x-3)(x-3)]

Hence, the zeroes are 3/7 and 3

Hope this helps!

If you think I helped, Please mark brainliest! Would really appreciate!

4 0

3 years ago

What is the asymptote for the graph of this logarithmic function?<br><br> f(x) = log3(x – 1)

Pepsi [2]

Answer:

Vertical Asymptote:

$x=1$

Horizontal asymptote:

it does not exist

Step-by-step explanation:

we are given

$f(x)=log_3(x-1)$

Vertical asymptote:

we know that vertical asymptotes are values of x where f(x) becomes +inf or -inf

we know that any log becomes -inf when value inside log is zero

so, we can set value inside log to zero

and then we can solve for x

$x-1=0$

we get

$x=1$

Horizontal asymptote:

we know that

horizontal asymptote is a value of y when x is +inf or -inf

For finding horizontal asymptote , we find lim x-->inf or -inf

$\lim_{x \to \infty} f(x)= \lim_{x \to \infty}log_3(x-1)$

$\lim_{x \to \infty} f(x)=log_3(\infty-1)$

$\lim_{x \to \infty} f(x)=undefined$

so, it does not exist

7 0

3 years ago

Read 2 more answers

Which number is question 7

Vedmedyk [2.9K]

Answer:

I don't understand too...

3 0

3 years ago

A TV studio has brought in 8 boy kittens and 10 girl kittens for a cat food commercial.

kondor19780726 [428]

Answer:

0.323 = 32.3% probability that the director chooses 3 boy kittens and 5 girl kittens.

Step-by-step explanation:

The kittens are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

A TV studio has brought in 8 boy kittens and 10 girl kittens for a cat food commercial.

This means that $N = 8 + 10 = 18$

We want 3 boys, so $k = 8$

The director is going to choose 8 of these kittens at random to be in the commercial.

This means that $n = 8$

What is the probability that the director chooses 3 boy kittens and 5 girl kittens?

This is P(X = 3).

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 3) = h(3,18,8,8) = \frac{C_{8,3}*C_{10,5}}{C_{18,8}} = 0.323$

0.323 = 32.3% probability that the director chooses 3 boy kittens and 5 girl kittens.

3 0

3 years ago