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nordsb [41]
3 years ago
12

A research company found that 11% of the people that they called agreed to participate in a survey. If the company called 196 pe

ople, about how many would be expected to participate in the survey?
A-50
B-40
C-20
D-10
I NEED HELP NOW IT'S IMPORTANT!!
Mathematics
2 answers:
natita [175]3 years ago
7 0

Answer:

B

Step-by-step explanation:

Trust me

Karolina [17]3 years ago
6 0
C

Explanation: if you were to multiply since you trying to find the 11% of people you will get 21.56 which rounds to 20
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Please help me solve #9, and please 10
german

Answer:

#9. y = -250x

#10. y = -2500, x = 100

Step-by-step explanation:

y = mx +b

y: y-value

m: slope

x: x-value

b: y-intercept

since your answer for #8 is -250, the slope would be -250 or m would be -250

y = -250x+b

now to solve for b, we take one of the points and plug it in, any works, but we'll use (1,-250)

plug in the points

-250 = -250(1)+b

solve for b

b = 0

thus the equation is y = -250x + 0 or y = -250x

#10 plug in x values and y values into equation to get answer

x = 10 -> y = -250(10) = -2500

y = -25,000 -> -25,000 = -250x

x = -25,000/-250

x = 100

6 0
2 years ago
What value of LaTeX: xx is in the solution set of 4x - 12 <16+8x
polet [3.4K]
I think it’s letter D.
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3 years ago
How do I solve the inequality, graph the solution set, and write it in interval notation for -8x+3 ≥ 3(6-x)?​
Ksju [112]

Answer:

I only know how to solve it, it is -3

Step-by-step explanation:

-8x+3> or = 18-3x

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5 0
3 years ago
I already solved this problem. I just need help with the HINT part.
frutty [35]
x+y=25 \\ y=25-x~~Other~number~in~terms~of~x \\ \\ x^2+y^2=313 \\ x^2+2xy+y^2=313+2xy \\ (x+y)^2=313+2x(25-x) \\ \frac{25^2-313}{2} =25x-x^2 \\ x^2-25x+156 \\ \\ \Delta =(-25)^2-4\times 1\times 156 \\ \Delta =625-624 \\ \sqrt{\Delta}=1 \\ \\ x= \frac{25 \pm 1}{2} \\ x= \left \{ {{x_1=13} \atop {x_2=12}} \right.

     The number "x" is given by:
y= \left \{ {{y_1=25-13 \rightarrow~y_1=12} \atop {y_1=25-12 \rightarrow ~y_1=13}} \right.
  
     Therefore, we have:

\boxed {S=({12,13})} \rightarrow~The~curly~braces~does~not~want~appear~here.
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