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ZanzabumX [31]
3 years ago
8

Which of these are accepted as true without proof?

Mathematics
2 answers:
Nataliya [291]3 years ago
8 0
The answer to the question is c
dimulka [17.4K]3 years ago
7 0
Opinions because they are never wrong its just what you think not anyone else

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25,00 people took part in a cross-country race The number of adults was 4 times the number of children there were 1,200 men.How
erastovalidia [21]

Answer:

Step-by-step explanation:

number of people= 2500

number of children =x

number of adults = 4x

so,  4x+x= 2500

x= 2500/5=500 children

number of men = 1200

number of women = 2500-(1200+500)= 800

4 0
3 years ago
To measure a stone face carved on the side of a​ mountain, two sightings 900 feet from the base of the mountain are taken. If th
olga nikolaevna [1]

Answer:

Height of the stone​ face = 66.29 feet

Step-by-step explanation:

Refer the given figure, here we need to find height of the stone​ face,

Height of the stone​ face = CD

CD = AD - AC

In ΔABC we have

             tan31=\frac{AC}{AB}\\\\tan31=\frac{AC}{900}\\\\AC=540.77feet

In ΔABD we have

             tan34=\frac{AD}{AB}\\\\tan34=\frac{AD}{900}\\\\AD=607.06feet

CD = AD - AC = 607.06 - 540.77 = 66.29 feet

Height of the stone​ face = CD = 66.29 feet

7 0
3 years ago
Y+4/12-y-1/12=y/2<br><br> Pls! on a time limit
icang [17]

Answer:

y= 1/2

Step-by-step explanation:

5 0
3 years ago
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What is the volume of the sphere shown below? 13 A. 527 units O B. 676 3 i units 3 C. 8788 3 i units 3 O D. 10472 units3​
vichka [17]
527, because it is hope it helps
6 0
2 years ago
HELP PLEASE MATH!! A company is testing tires for wear and tear. A given tire is said to either pass the test (P) or fail the te
Xelga [282]

Answer:

  PPF, PFF

Step-by-step explanation:

There are several ways you can list all the possible combinations. A couple of my favorite are a) use a binary counting sequence; b) use a gray code counting sequence.

Using the first method, the binary numbers 000 to 111 can be listed in numerical order as 000, <em>001</em>, 010, <em>011</em>, 100, 101, 110, 111. Letting 0=P and 1=F, the ones missing from your list are the ones in italics in my list.

Using the second method, we change the right-most character, then the middle one, and finally the left-most character so there is one change at a time: 000, <em>001</em>, <em>011</em>, 010, 110, 111, 101, 100.

After you have a list of all possible combinations, it is a simple matter to compare the given list to the list of possibilities to see which are missing.

5 0
3 years ago
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