Split 33 into two numbers that when added up are 33.
So 12 to 21, which when divided by 3, are 4 to 7.
Answer: x = 3, y = 1, z = 2
<u>Step-by-step explanation:</u>
EQ 1: x - y - z = 0
EQ 3:<u> -x + 2y + z = 1 </u>
y = 1
EQ 2: 2x - 3y + 2z = 7 → 1(2x - 3y + 2z = 7) → 2x - 3y + 2z = 7
EQ 3: -x + 2y + z = 1 → -2( -x + 2y + z = 1) → <u>-2x + 4y + 2z = 2</u>
y + 4z = 9
y = 1 ⇒ 1 + 4z = 9
4z = 8
z = 2
Input y = 1 and z = 2 into one of the equations to solve for x:
EQ 1: x - y - z = 0
x - (1) - (2) = 0
x - 3 = 0
x = 3
Check:
EQ 2: 2x - 3y + 2z = 7
2(3) - 3(1) + 2(2) = 7
6 - 3 + 4 = 7
3 + 4 = 7
7 = 7 
Answer:
A
when you simplify the equation you get A
Answer:
a possible solution is (10,1)
Step-by-step explanation:
Here, we want to solve the given inequality and determine one possible solution
From the question, we have it that;
x + y ≤ 13
Mathematically, we have it that 1 dime is worth $0.1
A nickel is worth $0.05
0.1x + 0.05y ≥ 0.95
please check the attachment for the graph of both equations
The point of intersection represents the solution.
we have a point here as (10,1)