Hello:
(5x^3)(2x)^3 = (5x^3)(2)^3(x)^3 = <span>(5x^3)8x^3=40x^6 ... (answer C)</span>
Answer:
1st One goes to the third one
2nd one goes to the 1st one
3rd one goes to the 4th one
and the 4th one goes to the 2nd one
Answer:
The two iterations of f(x) = 1.5598
Step-by-step explanation:
If we apply Newton's iterations method, we get a new guess of a zero of a function, f(x), xₙ₊₁, using a previous guess of, xₙ.
xₙ₊₁ = xₙ - f(xₙ) / f'(xₙ)
Given;
f(xₙ) = cos x, then f'(xₙ) = - sin x
cos x / - sin x = -cot x
substitute in "-cot x" into the equation
xₙ₊₁ = xₙ - (- cot x)
xₙ₊₁ = xₙ + cot x
x₁ = 0.7
first iteration
x₂ = 0.7 + cot (0.7)
x₂ = 0.7 + 1.18724
x₂ = 1.88724
second iteration
x₃ = 1.88724 + cot (1.88724)
x₃ = 1.88724 - 0.32744
x₃ = 1.5598
To four decimal places = 1.5598
Answer:
c
Step-by-step explanation:
=1/81
=3
=
=1/81
Answer:
8+7=21
Step-by-step explanation:
