Answer:
The probability that the aircraft is overload = 0.9999
Yes , The pilot has to be take strict action .
Step-by-step explanation:
P.S - The exact question is -
Given - Before every flight, the pilot must verify that the total weight of the load is less than the maximum allowable load for the aircraft. The aircraft can carry 37 passengers, and a flight has fuel and baggage that allows for a total passenger load of 6,216 lb. The pilot sees that the plane is full and all passengers are men. The aircraft will be overloaded if the mean weight of the passengers is greater than 6216/37 = 168 lb. Assume that weight of men are normally distributed with a mean of 182.7 lb and a standard deviation of 39.6.
To find - What is the probability that the aircraft is overloaded ?
Should the pilot take any action to correct for an overloaded aircraft ?
Proof -
Given that,
Mean, μ = 182.7
Standard Deviation, σ = 39.6
Now,
Let X be the Weight of the men
Now,
Probability that the aircraft is loaded be
P(X > 168 ) = P(
)
= P( z >
)
= P( z > -0.371)
= 1 - P ( z ≤ -0.371 )
= 1 - P( z > 0.371)
= 1 - 0.00010363
= 0.9999
⇒P(X > 168) = 0.9999
As the probability of weight overload = 0.9999
So, The pilot has to be take strict action .
Answer:
D) It is doubled
Step-by-step explanation:
Regardless of the side length, if the area of a square is quadrupled, the side lengths get doubled, as shown in the diagram. If all of the side lengths are doubled, that means the perimeter is also doubled.
Answer:
x+2/5x
Step-by-step explanation:
x%of 40 is 2/5x
...40 increased by x% of it self = x+2/5x
Answer:
The difference between the pulse rate of 36 beats per minute and the mean pulse rate for females is 42 beats per minute.
Step-by-step explanation:
We are given that for a data set of the pulse rates of adult females, the lowest pulse rate is 36 beats per minute, the mean of the listed pulse rate is x = 78.0 beats per minute, and their standard deviation is s = 13.7 beats per minute.
The mean pulse rate for females =
= 78.0 beats per minute
The standard deviation of the listed pulse rate = s = 13.7 beats per minute
The given pulse rate is = 36 beats per minute
So, the difference between the pulse rate of 36 beats per minute and the mean pulse rate for females is given by;
=
- 36
= 78 - 36 = 42 beats per minute
Hence, the required difference is 42 beats per minute.