Answer:
you have to make x-3 and x-7 equal to zero...
x = 3 or x=7
"A"
Step-by-step explanation:
Let
x ----------> the height of the whole poster
<span>y ----------> the </span>width<span> of the whole poster
</span>
We need
to minimize the area A=x*y
we know that
(x-4)*(y-2)=722
(y-2)=722/(x-4)
(y)=[722/(x-4)]+2
so
A(x)=x*y--------->A(x)=x*{[722/(x-4)]+2}
Need to minimize this function over x > 4
find the derivative------> A1 (x)
A1(x)=2*[8x²-8x-1428]/[(x-4)²]
for A1(x)=0
8x²-8x-1428=0
using a graph tool
gives x=13.87 in
(y)=[722/(x-4)]+2
y=[2x+714]/[x-4]-----> y=[2*13.87+714]/[13.87-4]-----> y=75.15 in
the answer is
<span>the dimensions of the poster will be
</span>the height of the whole poster is 13.87 in
the width of the whole poster is 75.15 in
<span>$8.50/hr multiplied by 16 hours worked equals $136. $136 minus (7.65%)(136) equals $125.60. $125.60 minus (9.15%)(136) equals $113.16. Travel expenses of $6.00 multiplied by 4 equals $24. $113.16 minus 24 equals $89.16 net income.</span>
40 hours at 5.90 a hour so 40 hours he would make 236
Answer: I think the correct answer is D.
