In this question, you're solving for a.
Solve for a:
-8(1 - a) =-7 -(1 - 3a)
<em>use the distributive property</em>
-8 + 8a = -7 -(1 - 3a)
-8 + 8a = -7 - 1 + 3a
<em>combine like terms</em>
-8 + 8a = -8 + 3a
<em>subtract 3a from both sides</em>
-8 + 5a = -8
<em>add 8 to both sides</em>
5a = 0
<em>divide both sides by 5</em>
a = 0
The total revenue for the event would the total amount earned from the tickets sold. So if x people attended the event, then there would be $(161x). We must keep in mind though the the maximum seating is 76 876. That means that the maximum revenue that can be earned must not exceed $(161)(76 867) = .
Hence we have f(x) = 161x where 0 ≤ x ≤ 76867.
From this, we can see that the domain is [0, 76867] while range is [0, 12375587]<span>.</span>
Answer:
B
Step-by-step explanation:
Data set D does not contain the value 128, which is the median value.
Data set C does not contain the outlier value 91.
Data set A contains value 168, which does not show up on the plot.
The only remaining choice is B.
_____
In order, the data values of set B are ...
... 91, 114, 120, 126, 128, 128 134, 136, 139, 142, 152
The median value of these 11 is the 6th one: 128. The median values of the remaining two sets of 5 are 120 and 139, making these values the quartiles at the ends of the box. The value 91 is more than 1.5 times the IQR (19) below the 1st quartile, so is considered an outlier. (The cutoff is 120-1.5·19=91.5.)
Step-by-step explanation:
do you that is responsible for that another is probability
