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3 years ago

Can anybody solve this

Mathematics

1 answer:

Alborosie3 years ago

5 0

Answer:

NP = $\frac{32}{9}$

Step-by-step explanation:

Since MP is an angle bisector then it divides the sides/ base in the ratio.

$\frac{MQ}{QP}$ = $\frac{MN}{NP}$ , substitute values

$\frac{18}{4}$ = $\frac{16}{NP}$ ( cross- multiply )

18NP = 64 ( divide both sides by 18 )

NP = $\frac{64}{18}$ = $\frac{32}{9}$

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Blood pressure values are often reported to the nearest 5 mmHg (100, 105, 110, etc.). The actual blood pressure values for nine

Paladinen [302]

Answer:

a) 117.4

b) 117.9

c) Option A) When there is rounding or grouping, the median can be highly sensitive to small change

Step-by-step explanation:

We are given the following data set in the question:

108.6, 117.4, 128.4, 120.0, 103.7, 112.0, 98.3, 121.5, 123.2

$Median:\\\text{If n is odd, then}\\\\Median = \displaystyle\frac{n+1}{2}th ~term \\\\\text{If n is even, then}\\\\Median = \displaystyle\frac{\frac{n}{2}th~term + (\frac{n}{2}+1)th~term}{2}$

n = 9

a) Median of the reported blood pressure values

Sorted Values: 98.3, 103.7, 108.6, 112.0, 117.4, 120.0, 121.5, 123.2, 128.4

Median =

$\dfrac{9 + 1}{2}^{th}\text{ term} = 5^{th}\text{ term} = 117.4$

b) New median of the reported values

Data: 108.6, 117.9, 128.4, 120.0, 103.7, 112.0, 98.3, 121.5, 123.2

Sorted Values: 98.3, 103.7, 108.6, 112.0, 117.9, 120.0, 121.5, 123.2, 128.4

New Median =

$\dfrac{9 + 1}{2}^{th}\text{ term} = 5^{th}\text{ term} = 117.9$

c) Since median is a position based descriptive statistics, a small change in values can bring a change in the median value as the order of the data may change.

Option A) When there is rounding or grouping, the median can be highly sensitive to small change

7 0

3 years ago

Solve by factoring : x^2-5x-36=0

il63 [147K]

Answer:

-9 and +4 are the factors

Step-by-step explanation:

-9 times +4 is -36 and if you add +4 to -9, you get -5.

After this your function will look like this:

$x^2-9x+4x-36$