Just add all the sides its really easy i would have done it but i cant see the squares that are on the paper or pc idk
Hope that helped!
if it didnt help just let me know and ill hlp you even more !
Answer:
Step-by-step explanation:
x = larger number, y = smaller number
x + y = 57
x = 2y - 3
2y - 3 + y = 57
3y - 3 = 57
3y = 57 + 3
3y = 60
y = 60/3
y = 20 <=== the smaller number
x = 2y - 3
x = 2(20) - 3
x = 40 - 3
x = 37 <=== the larger number
Answer:
a) 20<h≤30.
b) 26.17 hrs
Step-by-step explanation:
The missing table is shown in attachment.
Part a)
We need to find the class interval that contains the median.
The total frequency is
The median class corresponds to half
That is the 15th value.
We start adding the frequency from the top obtain the least cumulative frequency greater or equal to 15.
2+8+9=19
This corresponds to the class interval 20<h≤30.
Adding from the bottom also gives the same result.
Therefore the median class is 20<h≤30.
b) Since this is a grouped data we use the midpoint to represent the class.
The median is given by :
Answer:
<h2>g(f(x)) = x² - 3</h2>
Step-by-step explanation:
f(x) = x²
g(x) = x - 3
In order to find g(f(x)), substitute f(x) into g(x), that's for every x in g(x) replace it with f(x)
We have
g(f(x)) = x² - 3
Hope this helps you
X² + 1 = 0
=> (x+1)² - 2x = 0
=> x+1 = √(2x)
or x - √(2x) + 1 = 0
Now take y=√x
So, the equation changes to
y² - y√2 + 1 = 0
By quadratic formula, we get:-
y = [√2 ± √(2–4)]/2
or √x = (√2 ± i√2)/2 or (1 ± i)/√2 [by cancelling the √2 in numerator and denominator and ‘i' is a imaginary number with value √(-1)]
or x = [(1 ± i)²]/2
So roots are [(1+i)²]/2 and [(1 - i)²]/2
Thus we got two roots but in complex plane. If you put this values in the formula for formation of quadratic equation, that is x²+(a+b)x - ab where a and b are roots of the equation, you will get the equation
x² + 1 = 0 back again
So it’s x=1 or x=-1
