Answer:
What? Hey no no no yes what no no yes what yes yes
The perimeter of a two-dimensional figure is always the sum of its sides.
The exercise mat has a perimeter (P) of <u>36 feet</u>. ...
Let length be <em>L</em>, and width be <em>W</em>.
P = 36
L = 2w
P=2(l+w)=2·(12+6)=36
L = 12 feet
W = 6 feet
Answer: They were not correct it was bigger by 2.5 so the people were wrong
5 % of the students choose other. 95% choose either Saturday or Sunday.
Let x be the number of students who participated.
(5/100) * x = 8 Multiply both sides by 100
5 * x = 8*100
5*x = 800 Divide by 5
x = 800/5
x = 160 students participated in the survey <<<<< Answer
Answer: Dimensions of A are of length [L]
Dimensions of B are of 
Dimensions of C are of 
Step-by-step explanation:
The given equation is

Since the dimension on the L.H.S of the equation is [L] , each of the terms on the right hand side should also have dimension of length[L] to be dimensionally valid
Thus
Dimensions of A = [L]
Dimensions of Bt = [L]
![Bt=[L]\\\\](https://tex.z-dn.net/?f=Bt%3D%5BL%5D%5C%5C%5C%5C)
![[B][T]=[L]](https://tex.z-dn.net/?f=%5BB%5D%5BT%5D%3D%5BL%5D)
![\\\\\therefore [B]=LT^{-1}](https://tex.z-dn.net/?f=%5C%5C%5C%5C%5Ctherefore%20%5BB%5D%3DLT%5E%7B-1%7D)
Similarly
Dimensions of ![Ct^{}2 = [L]](https://tex.z-dn.net/?f=Ct%5E%7B%7D2%20%3D%20%5BL%5D)
![Ct^{2}=[L]\\\\[C][T]^{2}=[L]\\\\\therefore [C]=LT^{-2}](https://tex.z-dn.net/?f=Ct%5E%7B2%7D%3D%5BL%5D%5C%5C%5C%5C%5BC%5D%5BT%5D%5E%7B2%7D%3D%5BL%5D%5C%5C%5C%5C%5Ctherefore%20%5BC%5D%3DLT%5E%7B-2%7D)