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3 years ago

What is the area of the kite?

Mathematics

1 answer:

Alona [7]3 years ago

7 0

Answer:

im not fully sure because im a 4th grader but 52 i think.

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1. Find the value of x.<br> 2. Find the value of y.

DiKsa [7]

Answer:

$5y + 85 = 180 \\ 5y = 10 - 85 \\ 95 \div 5 = 19 \\ 5x + 95 = 180 \\ 5x = 180 - 95 \\ 5x = 85 \\ x = 17$

5 0

2 years ago

Read 2 more answers

In circle o, mZWBY = 72°.

likoan [24]

Answer:

Answer is B. 36 degrees

Step-by-step explanation:

From the diagram,

angle WBY = 2 × angle WXY

angle WBY = 72°

angle WXY =

$\frac{angle \: WBY}{2}$

$= \frac{72}{2}$

$= 36 \: degrees$

7 0

3 years ago

Jason is pulling a box across the room. He is pulling with a force of 11 newtons and his arm is making a 37 angle with the horiz

MissTica

Force=10N

Angle=37

Vertical componenets:-

$\\ \sf\longmapsto Fsin\theta$

$\\ \sf\longmapsto 10sin38$

$\\ \sf\longmapsto 10(0.6)$

$\\ \sf\longmapsto 6N$

4 0

2 years ago

There was no more rainfall for the rest of the day.

Aleonysh [2.5K]

There’s no exact value listed on this graph, but it would be where the line ends completely on the far right. The rain was fluctuating throughout the day when the graph was going up and down. when the graph completely stops, the rain did too.

5 0

3 years ago

Find the oth term of the geometric sequence 5,--25, 125,

Genrish500 [490]

Given the geometric progression below

$5,-25,125,\ldots$

The nth term of a geometric progression is given below

$T_n=ar^{n-1},\begin{cases}a=\text{first term} \\ r=\text{common ratio}\end{cases}$

From the geometric progression, we can deduce the following

$\begin{gathered} T_1=a=5 \\ T_2=ar=-25 \\ T_3=ar^2=125 \end{gathered}$

To find the value of r, we will take ratios of two consecutive terms

$\begin{gathered} \frac{T_2}{T_1}=\frac{ar}{a}=\frac{-25}{5} \\ \Rightarrow r=-5 \end{gathered}$

To find the 9th term of the geometric, we will have that;

$\begin{gathered} T_9=ar^8=5\times(-5)^8=5\times390625 \\ =1953125 \end{gathered}$

Hence, the 9th term of the geometric progression is 1953125

8 0

1 year ago