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3 years ago

9

Which of the following is the best example of a closed system?

2 answers:

xxMikexx [17]3 years ago

5 0

A greenhouse
all others are wrong

Marat540 [252]3 years ago

3 0

Based on my information, this would be known to be a "green house" as this, would be as it would be a house known for planting, and etc. But the main part that I wanted to consider would be the fact that it would also be a "closed system" as you would be able to open and close this kind of machine.

Your answer: a greenhouse

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8. What is the molarity of a CsOH solution if 30.0 mL of the solution is neutralized by 26.4 mL 0.25 M HBr solution (Hint: Ma x

anyanavicka [17]

Answer:

Remember, Molarity is moles of solute divided by Liters of solution. ... Hint: Don't forget to convert mL to L and use the formula Ma x Va = Mb x Vb. You are ... 8 What is the molarity of a CsOH solution if 30.0 mL of the solution is neutralized by 26.4 mL 0.25 M HBr solution ( Hint: Ma x Va = Mb x Vb. Rearrange to solve for Mb )? ..

Explanation:

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6 0

3 years ago

Read 2 more answers

How many atoms are present in 9.8g of H2SO4

aleksley [76]

Answer:

Explanation:

98 gH

2

SO

4

contains1 mole of H

2

SO

4

.

1 mole of H

2

SO

4

contain=1 mole of sulphur atoms.

∴9.8 g of H

2

SO

4

contain =0.1 mol of sulphur atom.

Thus, number of sulphur-atoms =n×N

A

(in 9.8 g of H

2

SO

4

)

=0.1×6.023×10

23

=0.6023×10

23

.

7 0

3 years ago

Do you think the Copper would have oxidized if it was completely submerged in vinegar why or why not?

Mama L [17]

Answer: Yes because of the mass of the object

Explanation:

5 0

3 years ago

The rapid decomposition of sodium azide, NaN3, to its elements is one of the reactions used to inflate airbags: 2 NaN3 (s)  2 N

masha68 [24]

<u>Answer:</u> The amount of nitrogen gas produced is 3.864 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

Given mass of $NaN_3$ = 6.00 g

Molar mass of $NaN_3$ = 65 g/mol

Putting values in equation 1, we get:

$\text{Moles of }NaN_3=\frac{6.00g}{65g/mol}=0.092mol$

For the given chemical reaction:

$2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)$

By Stoichiometry of the reaction:

2 moles of $NaN_3$ produces 3 moles of nitrogen gas

So, 0.092 moles of $NaN_3$ will produce = $\frac{3}{2}\times 0.092=0.138mol$ of nitrogen gas

Now, calculating the mass of nitrogen gas by using equation 1, we get:

Molar mass of nitrogen gas = 28 g/mol

Moles of nitrogen gas = 0.138 moles

Putting values in equation 1, we get:

$0.138mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(0.138mol\times 28g/mol)=3.864g$

Hence, the amount of nitrogen gas produced is 3.864 grams

7 0

3 years ago

Hows does one determine a molecular formula from the emprical formula?

Lynna [10]

Answer:

To determine a molecular formula from the empirical formula you need to know:

-the molecular mass

-calculate the empirical formula mass

-divide the molecular formular by the empirical formula mass

-multiply by this whole number the empirical formula

Explanation:

See the image below

3 0

4 years ago