8. What is the molarity of a CsOH solution if 30.0 mL of the solution is neutralized by 26.4 mL 0.25 M HBr solution (Hint: Ma x
Va = Mb x Vb. Rearrange to solve for Mb)? Ma = Molarity of Acid (M – mol/L)
Va = Volume of Acid (mL needs to be converted to L)
Mb = Molarity of Base (M – mol/L)
Vb = Volume of Base (mL needs to be converted to L)
CsOH = Base = What’s the molarity of the Base? = Mb
HBr = Acid = What’s the molarity of the acid? = Ma
Does the problem give you a volume for the acid? = Va
Does the problem give you a volume for the base? = Vb
Remember, Molarity is moles of solute divided by Liters of solution. ... Hint: Don't forget to convert mL to L and use the formula Ma x Va = Mb x Vb. You are ... 8 What is the molarity of a CsOH solution if 30.0 mL of the solution is neutralized by 26.4 mL 0.25 M HBr solution ( Hint: Ma x Va = Mb x Vb. Rearrange to solve for Mb )? ..
A chemical bond is created by either the transfer or sharing of electrons. Electrons with a missing full outer shell will be the ones participating in the bonding process. Hope this helped :)
