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Nina [5.8K]
3 years ago
8

8. What is the molarity of a CsOH solution if 30.0 mL of the solution is neutralized by 26.4 mL 0.25 M HBr solution (Hint: Ma x

Va = Mb x Vb. Rearrange to solve for Mb)?
Ma = Molarity of Acid (M – mol/L)
Va = Volume of Acid (mL needs to be converted to L)
Mb = Molarity of Base (M – mol/L)
Vb = Volume of Base (mL needs to be converted to L)
CsOH = Base = What’s the molarity of the Base? = Mb
HBr = Acid = What’s the molarity of the acid? = Ma
Does the problem give you a volume for the acid? = Va
Does the problem give you a volume for the base? = Vb

HBr + CsOH = CsBr + H2O 
Chemistry
2 answers:
anyanavicka [17]3 years ago
6 0

Answer:

Remember, Molarity is moles of solute divided by Liters of solution. ... Hint: Don't forget to convert mL to L and use the formula Ma x Va = Mb x Vb. You are ... 8 What is the molarity of a CsOH solution if 30.0 mL of the solution is neutralized by 26.4 mL 0.25 M HBr solution ( Hint: Ma x Va = Mb x Vb. Rearrange to solve for Mb )? ..

Explanation:

pls follow me

sergey [27]3 years ago
6 0

Answer:

0.22M

Explanation:

The equation for the reaction is given below:

HBr + CsOH —> CsBr + H2O

From the above, the mole ratio of the acid to base is 1.

Data obtained from the question include:

Ma = 0.25M

Va = 26.4mL

Mb =?

Vb = 30mL

Ma x Va = Mb x Vb

Mb = (Ma x Va) / Vb

Mb = ( 0.25x26.4 ) / 30

Mb = 0.22M

Therefore, the molarity of CsOH is 0.22M

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Cathodic protection of iron involves using another more reactive metal as a sacrificial anode. Classify each of the following me
Anika [276]

Answer:

a. Ag ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

b. Mg ---> can serve as a sacrificial anode for iron because it is higher than iron in the reactivity series. Hence, it is more reactive than iron.

c. Cu ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

d. Pb ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

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Explanation:

Cathodic protection of iron involves using another more reactive metal as a sacrificial anode. The reactivity series of metals arranges metals based on decreasing order of reactivity. The more reactive metals are found higher up in the series while the least reactive metals are found at the lower ends of the series. Thus, metals above iron in the reactivity series can serve as sacrificial anodes by protecting against corrosion, while those lower than iron cannot.

Based on the reactivity series, the following metals can be classified as either a sacrificial anode for iron or not:

a. Ag ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

b. Mg ---> can serve as a sacrificial anode for iron because it is higher than iron in the reactivity series. Hence, it is more reactive than iron.

c. Cu ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

d. Pb ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

e. Sn ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

f. Zn ---> can serve as a sacrificial anode for iron because it is higher than iron in the reactivity series. Hence, it is more reactive than iron.

g. Au ---> cannot serve as a sacrificial anode for iron because it is lower than iron in the reactivity series. Hence, it is less reactive than iron.

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