<u>Answer:</u> The amount of nitrogen gas produced is 3.864 grams
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
Given mass of
= 6.00 g
Molar mass of
= 65 g/mol
Putting values in equation 1, we get:
![\text{Moles of }NaN_3=\frac{6.00g}{65g/mol}=0.092mol](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DNaN_3%3D%5Cfrac%7B6.00g%7D%7B65g%2Fmol%7D%3D0.092mol)
For the given chemical reaction:
![2NaN_3(s)\rightarrow 2Na(s)+3N_2(g)](https://tex.z-dn.net/?f=2NaN_3%28s%29%5Crightarrow%202Na%28s%29%2B3N_2%28g%29)
By Stoichiometry of the reaction:
2 moles of
produces 3 moles of nitrogen gas
So, 0.092 moles of
will produce =
of nitrogen gas
Now, calculating the mass of nitrogen gas by using equation 1, we get:
Molar mass of nitrogen gas = 28 g/mol
Moles of nitrogen gas = 0.138 moles
Putting values in equation 1, we get:
![0.138mol=\frac{\text{Mass of nitrogen gas}}{28g/mol}\\\\\text{Mass of nitrogen gas}=(0.138mol\times 28g/mol)=3.864g](https://tex.z-dn.net/?f=0.138mol%3D%5Cfrac%7B%5Ctext%7BMass%20of%20nitrogen%20gas%7D%7D%7B28g%2Fmol%7D%5C%5C%5C%5C%5Ctext%7BMass%20of%20nitrogen%20gas%7D%3D%280.138mol%5Ctimes%2028g%2Fmol%29%3D3.864g)
Hence, the amount of nitrogen gas produced is 3.864 grams