If these teams are pulling with the same amount of force what will happen?

What is the mass of carbon in 290 g of CO2?

Elis [28]

Answer:

The mass of CO22 in total is 264 g.

The atomic mass for C is 12 g / mole.

The molar mass for CO22 is (12 + (2 × 16)) = 44 g / mole.

m C = (12 / 44) × 264 = 72 g

So, there are 72 g of C in 264 g of CO2

Explanation:

there's the answer have a good day.

4 0

3 years ago

What type of change is this picture showing?

sladkih [1.3K]

Answer: physical

Explanation: freezing and melting are physical changes.

8 0

3 years ago

How are they related "atom" "molecule"

zhenek [66]

Answer:

mixture of atoms forms molecule

7 0

3 years ago

Read 2 more answers

Name each subatomic particle, its charge, and its location in an atom.

Tpy6a [65]

Protons: charge +1, have a mass of 1 and are found in the nucleus

Neutrons: charge 0, have a mass of 1 and are found in the nucleus

Electrons: charge -1, have a mass of 1/840 and are found on the outside of the nucleus

hope that helps

4 0

3 years ago

Assuming the volumes are additive, what is the [Cl−] in a solution obtained by mixing 297 mL of 0.675 M KCl and 664 mL of 0.338

Elden [556K]

Answer: The concentration of chloride ions in the solution obtained is 0.674 M

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}$ .....(1)

For KCl:

Molarity of KCl solution = 0.675 M

Volume of solution = 297 mL

Putting values in equation 1, we get:

$0.675=\frac{\text{Moles of KCl}\times 1000}{297}\\\\\text{Moles of KCl}=\frac{(0.675mol/L\times 297)}{1000}=0.200mol$

1 mole of KCl produces 1 mole of chloride ions and 1 mole of potassium ion

Moles of chloride ions in KCl = 0.200 moles

For magnesium chloride:

Molarity of magnesium chloride solution = 0.338 M

Volume of solution = 664 mL

Putting values in equation 1, we get:

$0.338=\frac{\text{Moles of }MgCl_2\times 1000}{664}\\\\\text{Moles of }MgCl_2=\frac{(0.338mol/L\times 664)}{1000}=0.224mol$

1 mole of magnesium chloride produces 2 moles of chloride ions and 1 mole of magnesium ion

Moles of chloride ions in magnesium chloride = $(2\times 0.224)=0.448mol$

Calculating the chloride ion concentration, we use equation 1:

Total moles of chloride ions in the solution = (0.200 + 0.448) moles = 0.648 moles

Total volume of the solution = (297 + 664) mL = 961 mL

Putting values in equation 1, we get:

$\text{Concentration of chloride ions}=\frac{0.648mol\times 1000}{961}\\\\\text{Concentration of chloride ions}=0.674M$

Hence, the concentration of chloride ions in the solution obtained is 0.674 M

5 0

3 years ago