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SIZIF [17.4K]
3 years ago
11

The matrix 1 2 4(0 1 6/7 is being used to solve a system of equations. The solution to the system is

Mathematics
1 answer:
loris [4]3 years ago
5 0
| 1 2 ||x| = |4| - | 3 -1 ||y| |6| <span>-3 | 1 2||x| = |4| </span>
<span>| 3 -1||y| |6| </span>

<span>|-3 -6||x| = |-12| </span>
<span>| 3 -1||y| |6 | </span>


<span>| 0 -7 ||x| = | -6 | </span>
<span>| 3 -1 ||y| | 6 | </span>

<span>y = 6/7 </span>

<span>x = 16/7</span>
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Find the coordinates of the point (x,y,z) on the planez=4x+3y+1 which is closest to the origin.
Nataliya [291]
Given plane &Pi; : f(x,y,z) = 4x+3y-z = -1
Need to find point P on &Pi;  that is closest to the origin O=(0,0,0).

Solution:
First step: check if O is on the plane &Pi; : f(0,0,0)=0 &ne; -1 => O is not on &Pi;
Next:
We know that the required point must lie on the normal vector <4,3,-1> passing through the origin, i.e. 
P=(0,0,0)+k<4,3,-1> = (4k,3k,-k)
For P to lie on plane &Pi; , it must satisfy
4(4k)+3(3k)-(-k)=-1
Solving for k
k=-1/26
=>
Point P is (4k,3k,-k) = (-4/26, -3/26, 1/26) = (-2/13, -3/26, 1/26)
because P is on the normal vector originating from the origin, and it satisfies the equation of plane &Pi;
Answer: P(-2/13, -3/26, 1/26) is the point on &Pi; closest to the origin.

8 0
3 years ago
Need help please :) I’m not sure how to solve this one either
Andrews [41]
The answer is

580|21

6 0
1 year ago
Read 2 more answers
The mode of the data above is 6
nordsb [41]
I was stuck on the same thing in my class test. I ended up failing but if I get the answers to it I’ll totally send them to you
7 0
3 years ago
Which second-degree polynomial function has a leading coefficient of –1 and root 5 with multiplicity 2?
PIT_PIT [208]
A second degree polynomial function has the general form:

                  \displaystyle{f(x)=ax^2+bx+c, where a\neq0.

The leading coefficient is a, so we have a=-1.

5 is a double root means that :

i) f(5)=0,
ii) the discriminant D is 0, where D=b^2-4ac.

Substituting x=5, we have

                                        f(5)=a(5)^2+b(5)+c,

and since f(5)=0, and a is -1 we have:

                                          0=-25+5b+c
thus c=25-5b.


By ii) \displaystyle{b^2-4ac=0.

Substituting a with -1 and c with 25-5b we have:
                                     
          \displaystyle{b^2-4ac=0
          \displaystyle{b^2-4(-1)(25-5b)=0
          \displaystyle{b^2+4(25-5b)=0
          \displaystyle{b^2-20b+100=0
          \displaystyle{(b-10)^2=0
          \displaystyle{b=10 


Finally we find c: c=25-5b=25-50=-25

Thus the function is        \displaystyle{f(x)=-x^2+10x-25


Remark: It is also possible to solve the problem by considering the form

f(x)=-1(x-5)^2 directly.

In general, if a quadratic function has leading coefficient a, and has a root r of multiplicity 2, then its form is f(x)=a(x-r)^2
5 0
3 years ago
Read 2 more answers
HELP ME PLEASE I NEED TO FINISH ALGEBRA TODAY ITS URGENT I BEG YOU I DONT HAVE TIME
WARRIOR [948]
#66 Dimensions of matrix: The dimensions of a matrix are
[number of rows (across) x number of columns (up and down)]
There is 1 row and 4 columns, hence the dimensions of [1 x 4]

#71: use factor/label conversion method.
480 minutes    1 hour            480 hours        8 hours
                     * --------------  = --------------  = 
                       60 minutes      60 minutes

#72: common difference is how you get from one number to the next in the sequence. So from 42 to 38, you subtract 4, and the pattern is subtract 4 for the whole sequence. So the common difference <em></em>is -4

#38: The midpoint is the middle of the two coordinates, so imagine when used to find mean by drawing a number line like 1 to 10 and the mean would be 5. What did you do? You added 1 and 10 and divided by 2.
You can use the same method for finding midpoints on the coordinate plane.
The formula for midpoint is <span><span>(<span><span>x1+x</span>2</span>)</span>,<span>(<span><span>y1+y</span>2</span>). So it's (5 + 2) , (8 + 7) which equals (7, 15).

#35: This is the same 3* x^(9*1/5) = 3*x^9/5
Remember square root of a number is the same as that number to the 1/2, and the same with all other roots. The fifth root of x is the same as x to the power of 1/5

#36: This is the same as 36*( x^5*3/2 * y^3*3/2), since you can put the power to each of the numbers almost like the distributive property.
= 36 * (x^15/2 * y^9/2)

Well #20 is <em>extremely</em><em> </em>easy. The solutions are anything that is shaded in the blue

The rightmost question is the same thing as #20. Anything not shaded is not a solution.

</span></span>
#64: Just like you learned in elementary school, the median is the middle number. The middle number is 10<span>

</span>
4 0
3 years ago
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