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SIZIF [17.4K]
3 years ago
12

How do I find the Q1, Q3, and IQR of a median that is a decimal?

Mathematics
1 answer:
bija089 [108]3 years ago
3 0
Step 1: Put the numbers in order.
1,2,5,6,7,9,12,15,18,19,27<span>Step 2: </span>Find the median (How to find a median).
1,2,5,6,7,9,12,15,18,19,27<span>Step 3: </span>Place parentheses around the numbers above and below the median. 
Not necessary statistically–but it makes Q1 and Q3 easier to spot.
(1,2,5,6,7),9,(12,15,18,19,27)<span>Step 4: </span>Find Q1 and Q3
Q1 can be thought of as a median in the lower half of the data. Q3 can be thought of as a median for the upper half of data.
(1,2,5,6,7),  9, ( 12,15,18,19,27). Q1=5 and Q3=18.<span>Step 5: </span>Subtract Q1 from Q3 to find the interquartile range.
18-5=13.
Hope this helped:) 
-BRIEMODEE:)
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I need a better explanation how to find length and area of a triangle
fomenos

Answer:

Height(h) = 24in

Area = 204in²

Step-by-step explanation:

we would use the heron formula because we have all the sides to calulate the area

S  = (A+B+C)/2 = (25 + 17 + 26)/2 = 68/2 = 34

area = √s(s-a)(s-b)(s-c)  = √34(34-25)(34-17)(34-26) = √34(9)(17)(8) = √34x9x17x8 = √41616 = 204

area= (1/2)bh

    204 = (1/2)bh b= 17, h =?

204 = (1/2)17h

204 x 2 = 17h

408 = 17h

h = 408/17 = 24in

Height(h) = 24in

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3 years ago
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e-lub [12.9K]

Answer:

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is your answer look it once

3 0
3 years ago
Bonjour
solmaris [256]
<span>3 + t = 2 x t + 7    t =4 et x=0   vraie
</span><span>9 x (t-6) = 3 x t     t=4 et x=0    vraie
</span><span>4 x (t - 1) = t x t     t=2 st x=0    vraie

No, 25 cm c'est un 40 ou 41
No 23 cm c'est un 37



</span>
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VashaNatasha [74]
Hey there!

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9 + 9 + 9 + 9 + 9 = 45

9 x 5 = 45 <----

2. I would use the same strategy as the first one, except add the number 8 five times . . .

8 + 8 + 8 + 8 + 8 = 40

8 x 5 = 40 <----

Hope this helps you.
Have a great day!
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