Answer:
The amount of invested money after a period of 4 years:
A = 200 x (1 + 9/100)^4 = 282.32 dollar
Hope this helps!
:)
Answer:
48
Step-by-step explanation:
You just have to divide the length of the fabric by the length of the sections
Answer:
The density of the bar of gold is 19.32 grams per cubic centimeter .
Step-by-step explanation:
Formula

As given
A bar of gold has a volume of 722 cubic centimeters and weighs 13.949 kilograms.
As 1 kilogram = 1000 gram
Than convert 13.949 kilograms into grams.
13.949 kilograms = 13.949 × 1000 grams
= 13949 grams
Mass = 13949 grams
Volume = 722 cubic centimeter
As put in the formula

Density = 19.32 grams per cubic centimeter (Approx)
Therefore the density of the bar of gold is 19.32 grams per cubic centimeter .
0.06 or you can just put 6.
Basically, you have to multiply 30% x 20.
Glad I could help☺️
Answer:
5.44 cm³
Step-by-step explanation:
The volume of the hexagonal nut can be found by multiplying the area of the end face by the length of the nut. The end face area is the difference between the area of the hexagon and the area of the hole.
The area of a hexagon with side length s is given by ...
A = (3/2)√3·s²
For s=1 cm, the area is ...
A = (3/2)√3(1 cm)² = (3/2)√3 cm²
__
The area of a circle is given by ...
A = πr²
The radius of a circle with diameter 1 cm is 0.5 cm. Then the area of the hole is ...
A = π(0.5 cm)² = 0.25π cm²
__
The volume is the face area multiplied by the length, so is ...
V = Bh = ((3/2)√3 -0.25π)(3) . . . . . cm³
V = (9/2)√3 -0.75π cm³ ≈ 5.44 cm³
The volume of the metal is about 5.44 cm³.