Given:
Vertical angles.
One angle is 85°.
To find:
The measure of ∠1, ∠2 and ∠3.
Solution:
∠2 and 85° are vertically opposite angles and ∠1 and ∠3 are vertically opposite angles.
Vertical angle theorem:
If two lines are intersecting, then the vertically opposite angles are congruent.
⇒ m∠2 = 85°
Sum of the adjacent angles in a straight line = 180°
m∠2 + m∠3 = 180°
85° + m∠3 = 180°
Subtract 85° from both sides.
85° + m∠3 - 85° = 180° - 85°
m∠3 = 95°
By vertical angle theorem:
⇒ m∠1 = m∠3
⇒ m∠1 = 95°
Therefore m∠1 = 95°, m∠2 = 85° and m∠3 = 95°.
What percent of 150=6
X/100 * 150=6
/150. /150
X/100=0.04
X/100 *100/1 =0.04* 100/1
X=4
4% of 150=6
That means that for every dollar they take 4 cents from each dollar
150*4 pennies would equal 600 pennies or 6$ or 6.00
Hope this helps!
The answer is 40%
Here is how I got it.
36/90* 100%= 2/5* 100%=2* 20%=40%
Given:
The expression is:
![(6m^5+3-m^3-4m)-(-m^5+2m^3-4m+6)](https://tex.z-dn.net/?f=%286m%5E5%2B3-m%5E3-4m%29-%28-m%5E5%2B2m%5E3-4m%2B6%29)
To find:
The resulting polynomial in standard form.
Solution:
We have,
![(6m^5+3-m^3-4m)-(-m^5+2m^3-4m+6)](https://tex.z-dn.net/?f=%286m%5E5%2B3-m%5E3-4m%29-%28-m%5E5%2B2m%5E3-4m%2B6%29)
Write subtraction of a polynomial expression as addition of the additive inverse.
![(6m^5+3-m^3-4m)+(m^5-2m^3+4m-6)](https://tex.z-dn.net/?f=%286m%5E5%2B3-m%5E3-4m%29%2B%28m%5E5-2m%5E3%2B4m-6%29)
Rewrite terms that are subtracted as addition of the opposite.
![6m^5+3+(-m^3)+(-4m)+m^5+(-2m^3)+4m+(-6)](https://tex.z-dn.net/?f=6m%5E5%2B3%2B%28-m%5E3%29%2B%28-4m%29%2Bm%5E5%2B%28-2m%5E3%29%2B4m%2B%28-6%29)
Group like terms.
![[6m^5+m^5]+[3+(-6)]+[(-m^3)+(-2m^3)]+[(-4m)+4m]](https://tex.z-dn.net/?f=%5B6m%5E5%2Bm%5E5%5D%2B%5B3%2B%28-6%29%5D%2B%5B%28-m%5E3%29%2B%28-2m%5E3%29%5D%2B%5B%28-4m%29%2B4m%5D)
Combine like terms.
![7m^5+(-3)+(-3m^3)+0](https://tex.z-dn.net/?f=7m%5E5%2B%28-3%29%2B%28-3m%5E3%29%2B0)
On simplification, we get
![7m^5-3-3m^3](https://tex.z-dn.net/?f=7m%5E5-3-3m%5E3)
Write the polynomial in standard form.
![7m^5-3m^3-3](https://tex.z-dn.net/?f=7m%5E5-3m%5E3-3)
Therefore, the required polynomial in standard form is
.
Answer:
idkcorsica
Step-by-step explanation:
idkhb4n4ut Henry