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3 years ago

Would a liquid’s refractive index measured at a high altitude be different from that measured at sea level?

1 answer:

6 0

By definition, refractive index is the ratio of the velocity of light in vacuum to the velocity of light in a specified medium. The medium here is the liquid. The speed of light through the liquid also depends on the temperature and pressure. At sea level, the liquid is higher in temperature and pressure. So, the speed is gonna be relatively slower because of the movement of atoms. At high altitude, the liquid is at a lower temperature and pressure. The movements of the molecules are lesser, thus, light can move much faster. So, yes, it would be different. The refractive index would be closer to 1 at high altitude, and greater than 1 at sea level.

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What is the weight of an object when the object has a mass of 22kg

Savatey [412]

Assuming the object is on earth the objects weight would be equal to its mass multiplied by the gravitational field constant

mass=22kg
g=9.80665N/kg

weight=(22 kg) (9.80665 N/kg)=215.7463N

generally g is rounded to be 10 N/kg so for any question where it asks the weight given the mass just multiply by 10 and that should suffice. In this case the answer would be 220 N

5 0

3 years ago

An object is dropped from a platform100 ft high. Ignoring wind resistance, what will its speed be when it reaches the ground?

sweet-ann [11.9K]

Answer:

80 ft/s

Explanation:

Given:

Δy = 100 ft

v₀ = 0 ft/s

a = 32.2 ft/s²

Find: v

v² = v₀² + 2aΔx

v² = (0 ft/s)² + 2 (32.2 ft/s²) (100 ft)

v = 80.2 ft/s

Rounded, the speed when it reaches the ground is 80 ft/s.

4 0

3 years ago

Scientists earlier believed that the lowest measurable temperature is the freezing point of ice. However, modern scientists beli

djverab [1.8K]

I think the correct answer from the choices listed above is the first option. The statement that best accounts for these different opinions would be that <span>scientists propose contradictory ideas to include all possibilities. Hope this answers the question. Have a nice day.</span>

5 0

3 years ago

Read 2 more answers

Approximately, What is the value of the Hubble Constant, as measured by scientists? Hypothetically, if the value of the Hubble C

Serhud [2]

Answer:

The current value of the Hubble's constant = 73 km/sec/Mpc.

t = 71.9 trillion years will be the new age of universe if the Hubble constant = 700 km/s/Mpc

Explanation:

The current value of the Hubble's constant = 73 km/sec/Mpc. However, recent discoveries in the cosmology contradicts the idea of Hubble constant as being fixed. Some scientists are not agreeing on this value and the debate is going on.

Hubble law states that how fast universe is expanding or in other words, galaxies are expanding separating with a speed directly proportional to the distance of galaxies to the earth.

Hence,

v is directly proportional to d

where, v = apparent velocity

d = distance

if we equate velocity and distance then there comes Hubble constant.

v = $H_{0}$ x d

$H_{0}$ = 73 km/sec/Mpc

where, Mpc = Mega Parsec = 1 Mpc = 3.086 x $10^{19}$ km

We can use Hubble constant to tell the age of universe.

t = d/v

t = d/( $H_{0}$ xd)

t = 1/ $H_{0}$

Scientist calculated the age of universe by using Hubble constant, which is 13.4 billion years.

Now, if we hypothetically change the value of Hubble constant,

from $H_{0}$ = 73 km/sec/Mpc to $H_{0}$ = 700 km/sec/Mpc

then the age of universe will be:

t = 1/ $H_{0}$

first convert the units of new $H_{0}$ into 1/s

$H_{0}$ = (700) x (/3.08 x $10^{19}$ )

$H_{0}$ = 227.27 x $10^{-19}$ = 2.27 x $10^{-21}$ 1/s

So,

Age of universe will be:

t = 1/ $H_{0}$ = 1/2.27x $10^{-21}$ 1/s

t = 2.27 x $10^{21}$ s

t = 71.9 trillion years

t = 71.9 trillion years will be the new age of universe if the Hubble constant = 700 km/s/Mpc

6 0

3 years ago

9. You drive a car from Milwaukee to Chicago, which is a distance of 150km and it takes you 95

Katena32 [7]

For this case we have to, by definition:

$v = \frac {x} {t}$

Where:

v: It's the velocity

x: It is the distance traveled

t: It is the time spent

1 hour equals 60 minutes and 1 minute equals 60 seconds.

On the other hand:

1 kilometer equals 1000 meters

So: $\frac {150} {95} \frac{km} {min} * \frac {1} {60} \frac {min} {sec} * \frac {1000} {1} \frac {m} {km} = \frac {150 * 1000} {95 * 60} \frac {m} {sec} = \frac {15000} {5700} \frac {m} {sec} = 2.63 \frac {m} {sec}$

On the other hand: $\frac {150} {95} \frac{km} {min} * \frac {60} {1} \frac {min} {hr} = \frac {150 * 60} {95} \frac {km} {h} = 94.74 \frac {km} {h}$

ANswer:

$2.63 \frac {m} {sec}\\94.74 \frac {km} {h}$

8 0

3 years ago