A 2000 kg truck is traveling at 5 m/s and collides with a 1000 kg car that is not moving. After the collision, the 2000 truck st
1 answer:
Answer:
A) 10 m/s
Explanation:
We know that according to conservation of momentum,
m1v1 + m2v2 = m1u1 + m2u2 ..............(equation 1)
where m1 and m2 are masses of two bodies, v1 and v2 are initial velocity before collision and u1 and u2 are final velocities after collision respectively.
From the given data
If truck and car are two bodies
truck : m1 = 2000 Kg v1 = 5 m/s u1 = 0
car : m2 = 1000 kg v2 = 0 u2 = ?
final velocity of truck and initial velocity of car are static because the objects were at rest in the respective time.
substituting the values in equation 1, we get
(2000 x 5) + 0 = 0 + (1000 x u2)
u2 = x 5
= 10 m/s
Hence after collision, car moves at a velocity of 10 m/s
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The concept required to solve this problem is related to thin film interference.
The path length difference between two waves one is reflected from top surface of the film and the bottom surface of the film is equal to twice the thickness of the film:
Where,
Path length difference
t = thickness
At the same time we have that the constructive interference condition for a thin film interference for strongly reflected rays is
Where
Path length difference
wavelength
m = Any integer (order of the equation) which represent the number of repetition of the spectrum
Equation both expression we have
Re-arrange to find the thickness we have
Our values are given as
m = 1
= 597nm
n = 1.38
Replacing,
Therefore the thinnest thickness of the film is 216.3nm