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disa [49]
3 years ago
9

1) How is chemical energy transformed into potential energy?

Physics
1 answer:
tia_tia [17]3 years ago
6 0

Answer:

Chemical potential energy is a form of potential energy related to the structural arrangement of atoms or molecules. This arrangement may be the result of chemical bonds within a molecule or otherwise. Chemical energy of a chemical substance can be transformed to other forms of energy by a chemical reaction.

Explanation:

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When light traveling in straight lines passes through an object that is curved like a lens, the light is ________ at different a
qwelly [4]

Answer:

You are right. It is reflected

Explanation:

if it is concave then the light is reflected at one direction.

if it is convex the light is reflected outwards and they will travel away from the focal point and the light scatters or will be reflected to different directions

3 0
2 years ago
A temperature of 20°C is equivalent to approximately?
umka21 [38]

The answer is A.68 degrees

7 0
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Please help<br> types of stimuli the sensory organs receive.
Alborosie

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Hope this helps(:

Explanation:

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3 years ago
A body is projected from the ground at an angle of 30° with the horizontal at an initial speed of 128 ft/s. Ignoring air frictio
Elanso [62]

Answer

given,

v = 128 ft/s

angle made with horizontal = 30°

now,

horizontal component of velocity

vx = v cos θ = 128 x cos 30° = 110.85 ft/s

vertical component of velocity

vy = v sin θ = 128 x sin 30° = 64 m/s

time taken to strike the ground

using equation of motion

v = u + at

0 =-64 -32 x t

t = 2 s

total time of flight is equal to

T = 2 t = 2 x 2 = 4 s

b) maximum height

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 v² = u² + 2 a h

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c) range

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4 0
3 years ago
An elevator starts from rest with a constant upward acceleration and moves 1 m in the first 1.7 s. A passenger in the elevator i
avanturin [10]

Answer: Tension = 53.6N

Explanation:

Given that

Height h = 1 m

Time t = 1.7 s.

Mass m = 5.1 kg 

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h = X0+ V0t + at2/2;

Th elevator starts from rest with a constant upward acceleration. Initial velocity Vo = 0, also Xo = 0; thus

a = 2h/t2 = 2 × 1/1.7^2

a = 0.69 m/s2.

Then we can find the tension in the cord by using the formula

T = mg + ma

= 5.1 (9.8 + 0.69)

= 5.1 × 10.5

= 53.6N

7 0
3 years ago
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