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3241004551 [841]
2 years ago
8

Which set of coefficients of the terms in the expansion of the binomial (x+y)^3 is correct ?

Mathematics
2 answers:
Aleonysh [2.5K]2 years ago
7 0
The expansion of (x+y)^3 is x^3 +3x^2×y+3x×y^2+y^3 the coefficients are 1,3,3,1
BigorU [14]2 years ago
4 0
We are technically FOILing this out... with a power of 3.

(x+y)(x+y)(x+y)

So we can first factor out the first two "x+y"s.

( x^{2} +2xy + y^{2} ), multiplied by the last "x+y".

x^{3} +3 x^{2} y +3x y^{2} + y^{3}

Coefficients are the number that comes in front of a variable. 

In this case, 1 comes in front of x^{3}, 3 comes in front of x^{2} y, 3 comes in front of x y^{2}, and 1 comes in front of y^{3}.

Thus: 1, 3, 3, 1.
         Answer Choice A
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You randomly select a marble from a bag.
AysviL [449]

Answer:

b is the answer

Step-by-step explanation:

3 0
3 years ago
What is the approximate length of the radius of a circle with a circumference of 63 inches?
Sergeeva-Olga [200]

Answer: 63/2π

Step-by-step explanation: C=πd  

                                             63=πd

                                             D=63/π

r=1/2d

1/2×63/π=<u>63/2π</u>

       

5 0
3 years ago
The areas of two similar triangles are 72dm2 and 50dm2. The sum of their perimeters is 226dm. What is the perimeter of each of t
zloy xaker [14]

Answer:

103=  p small

plarge = 123

Step-by-step explanation:

We know that the the ratio of the areas is the scale factor squared/

Larger triangle over smaller triangle

72

----- = scale factor ^2

50

simplify by dividing by 2 on top and bottom

36

----- = scale factor ^2

25

Take the square root of each side

sqrt(36)

-------------- = sqrt(scale factor ^2)

sqrt(25)

6

-------------- = scale factor

5

The ratio of the perimeters is the scale factor

p large             6

-------------- = ----------------

 p small                5

Using cross products

6 p large = 5 p small

We know the sum is 226

p large + p small = 226

p large = 226 - p small

We have 2 equation and 2 unknowns

6 p large = 5 p small

Substitute for p large

6 (226 - p small) = 5 p small

1356 - 6 p small = 5 p small

Add 6 p small to each side

1356 = 11 p small

divide by 11

1356/11 =  p small

P large = 226-1356/11

p large = 2486/11-1356/11

plarge = 1130/11

The solution requires whole number answers so

1356/11 =  p small

123.27 which rounds to 123

plarge = 1130/11

plarge = 102.7272 = 103

6 0
2 years ago
Write the answer in standard form.
viktelen [127]

Answer and step-by-step explanation:

We learn that (a+b)^3 = a^3 + 3a^2b + 3ab^2 + b^3

So in this case, it would be:

= x^3 + (3*x^2*2) + (3*x*2^2) + 2^3

= x^3 + 6x^2 + 3x * 4 + 8

= x^3 + 6x^2 + 12x + 8

This is the standard form of the equation

Hope it help you :3

6 0
3 years ago
Read 2 more answers
In your US History class, you have scores of 78, 89, 87 and 96 on the first four tests. To get a B, the average of the five test
Vaselesa [24]
Well, since it is asking for an average, we have to add
78+89+87+96=
350... then we divide by 4
which would be 87.5 which IS greater than 80 :)
and less than 90 :)

3 0
2 years ago
Read 2 more answers
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