What is the leg length of an isosceles right triangle with a hypotenuse of 32 inches?

2 answers:

5 0

Isosceleses means 2 sides have equal legnths
that means that those are the legs
a^2+b^2=c^2
a and b are legs and c is the hypotonuse

a=b
2a^2=c^2
c=32
2a^2=32^2
2a^2=1024
divide both sides by 2
a^2=512
sqrt both sides
a=16√2

the legnth of each leg is 16√2 or aprox 22.63 inches

natita [175]3 years ago

3 0

It would be about 22.63 for each leg

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Nadusha1986 [10]

Answer:

Ok so first you would have to turn them into improper fractions which is

3 $\frac{1}{2\\}$ = $\frac{7}{2}$ and 4 $\frac{2}{5}$ = $\frac{22}{5}$

So now that you have made them both improper fractions you have to find common denominators.

To find common denominators you must multiply both the numerator and the denominator by the same thing. Since your oposing fraction has a denominator of 5 you can know that a even number wont go in an odd number so take $\frac{22}{5}$ and mutiply both numbers by 2 and get $\frac{44}{10}$ . Then mutiply both numbers in $\frac{7}{2}$ by 5 to get a common denominator.