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3 years ago

I NEED HELP IN THIS QUESTION PLEASE

Mathematics

1 answer:

aliina [53]3 years ago

5 0

Looks like you got it right :) Each package contains 8 chocolates, so to find 8 containers, just multiply by 8 to get 64, which would be H.

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The liquid base of an ice cream has an initial temperature of 86°C before it is placed in a freezer with a constant temperature

Karolina [17]

The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

From Newton's law of cooling, we have that

$T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$

Where

$(t) = \ time$

$T_{(t)} = \ the \ temperature \ of \ the \ body \ at \ time \ (t)$

$T_{s} = Surrounding \ temperature$

$T_{0} = Initial \ temperature \ of \ the \ body$

$k = constant$

From the question,

$T_{0} = 86 ^{o}C$

$T_{s} = -20 ^{o}C$

∴ $T_{0} - T_{s} = 86^{o}C - -20^{o}C = 86^{o}C +20^{o}C$

$T_{0} - T_{s} = 106^{o} C$

Therefore, the equation $T_{(t)}= T_{s}+(T_{0} - T_{s})e^{kt}$ becomes

$T_{(t)}=-20+106 e^{kt}$

Also, from the question

After 1 hour, the temperature of the ice-cream base has decreased to 58°C.

That is,

At time $t = 1 \ hour$ , $T_{(t)} = 58^{o}C$

Then, we can write that

$T_{(1)}=58 = -20+106 e^{k(1)}$

Then, we get

$58 = -20+106 e^{k(1)}$

Now, solve for $k$

First collect like terms

$58 +20 = 106 e^{k}$

$78 =106 e^{k}$

Then,

$e^{k} = \frac{78}{106}$

$e^{k} = 0.735849$

Now, take the natural log of both sides

$ln(e^{k}) =ln( 0.735849)$

$k = -0.30673$

This is the value of the constant $k$

Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at $t = 2 \ hours$

From

$T_{(t)}=-20+106 e^{kt}$

Then

$T_{(2)}=-20+106 e^{(-0.30673 \times 2)}$

$T_{(2)}=-20+106 e^{-0.61346}$

$T_{(2)}=-20+106\times 0.5414741237$

$T_{(2)}=-20+57.396257$

$T_{(2)}=37.396257 \ ^{o}C$

$T_{(2)} \approxeq 37.40 \ ^{o}C$

Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C

Learn more here: brainly.com/question/11689670

6 0

2 years ago

Read 2 more answers

NEED HELP NOWWW Which of the following is a monomial?

Dafna11 [192]

Answer: C

Step-by-step explanation:

A monomial is a expression where in it is x to the power of something, and x cannot be a denominator

4 0

3 years ago

Which expression has an estimated product of 45?<br>44.7x2.1<br>7.5x84<br>8.7x5.28<br>38.1 x 7.3

Anni [7]

Answer: 8.7 x 5.28

We have to find that expression , which has an estimated product of

1.→44.7 x 2.1

2.→7.5 x 8.4

3.→8.7 x 5.28

4.→38.1 x 7.3

We will start from option 1.

→44.7 x 2.1

44.7 when estimated to nearest tenth=45

2.1, when estimated to nearest tenth=2

44.7 × 2.1=45×2=90

Option 2

7.5 x 8.4

7.5 when estimated to nearest tenth=8

8.4, when estimated to nearest tenth=8

⇒7.5 × 8.4=8×8=64

Option 3

8.7 × 5.28

8.7, when estimated to nearest tenth=9

5.28, when estimated to nearest tenth=5

⇒8.7 × 5.28=9×5=45

Option D

38.1 × 7.3

38.1 when estimated to nearest tenth=38

7.3, when estimated to nearest tenth=7

⇒38×7=266

Option C:⇒8.7 × 5.28 has an estimated product of 45

6 0

3 years ago

Read 2 more answers

If a set of test scores has a large range but a small standard deviation, describe what this means about students' performance o

Dafna11 [192]

Answer:

Step-by-step explanation:

6 0

1 year ago

Yousef borrowed 1,690 last term for tuition, books, and student fees. This term he plans to borrow 2,345 because he knows his cl

motikmotik

The estimate of the amount of money Yousef will borrow by first rounding to the hundred is 4000

<h3>Estimate the amount of money Yousef will borrow by first rounding to the hundred</h3>

The amount borrowed are given as:

Last term = 1690

This term = 2345

When the amounts are rounded to the nearest hundred, the amounts borrowed become:

Last term = 1700

This term = 2300

The total amount is then calculated as:

Total amount = Last term + This term

Substitute the known values in the above equation

Total amount = 1700 + 2300

Evaluate the sum

Total amount = 4000

Hence, the estimate of the amount of money Yousef will borrow by first rounding to the hundred is 4000