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worty [1.4K]
3 years ago
7

The two cones below are similar. What is the value of x?

Mathematics
2 answers:
Effectus [21]3 years ago
4 0

Answer:

Step-by-step explanation:

maks197457 [2]3 years ago
3 0

Answer:

.8

Step-by-step explanation:

The ratios have to be the same for the cones to be similar

10       4

----- = ------

2         x

Using cross products

10x = 4*2

10x = 8

Divide by 10

x = 8/10

x = .8

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PLEASE HELP ALMOST FINISHING ALBERA 1 PUT I NEED YOUR HELP PLEASE I BEG YOU BRAINLEST ANSWER!!!
tester [92]
59  is D 
because  with the point (-3,7) you substitute it into the equation, making it: 7=4x+b.  solve for b.  then you have y=4x+19.     work out the algebra in the possible choices and whatever equals y=4x+19 will be the answer. in this case, its D.


60 is C
same as above, you do the algebra of the equation. bring the one over after doing distribution with the 4 and voila!


61 is A
a relatively easy one, all you do is the the slope -4 where m goes, and 3 where b goes. y= -4x+3


62 is C.
this one requires more work.
chose one of the points, in this case (2,7) and put them into the equation. 
but wait, you need a slope! 
you get that use the formula (y2-y1)/(x2-x1) which will be
(7-5)/(2-3) which will be
-2.
now you have y-7= -2(x-2)
voila!



63 is  C.   y= 1/2x+3

64 is B. (3, -5)

66 is B. negative. the line  goes \ ( not / which is positive)

67 would be A. because it is positive and the I and the E are in the right places.


70 is C.  2/3.   as before, remember we can but the points into this equation and have (6-4)/(3-0) which = 2/3


71  is D.  y= 3x+10

72 is C. a third degree monomial

73 can't read


74 can't read 
 
75 can't read.

 
4 0
3 years ago
Allowance method entries
Feliz [49]

Using the Allowance Method, the relevant transactions can be completed in the books of Wild Trout Gallery as follows:

1. <u>Allowance for Doubtful Accounts</u>

Accounts                                          Debit       Credit

Jan. 1 Beginning balance                             $53,800

Jan. 19 Accounts Receivable                           2,560

Apr. 3 Accounts Receivable       $14,670

July 16 Accounts Receivable        19,725

Nov. 23 Accounts Receivable                         4,175

Dec. 31 Accounts Receivable       25,110

Dec. 31 Ending balance          $56,500

Dec. 31 Bad Debts Expenses                   $55,470

Totals                                        $116,005  $116,005

<u>Accounts Receivable</u>

Accounts                                          Debit               Credit

Jan. 1 Beginning balance           $2,290,000

Jan. 19 Allowance for Doubtful           2,560

Jan. 19 Cash                                                            $2,560

Apr. 3  Allowance for Doubtful                                14,670

July 16  Allowance for Doubtful                              19,725

July 16  Cash                                                             6,575

Nov. 23  Allowance for Doubtful         4,175

Nov. 23 Cash                                                             4,175

Dec. 31  Allowance for Doubtful                             25,110

Dec. 31   Sales Revenue            8,020,000

Dec. 31   Cash                                               $8,944,420

Dec. 31 Ending balance                                 $1,299,500

Totals                                        $10,316,735 $10,316,735

3. Expected net realizable value of the accounts receivable as of December 31 = $1,243,000 ($1,299,500 - $56,500)

Allowance for Doubtful Accounts ending balance = $40,100 ($8,020,000 x 0.5%)

<u>Allowance for Doubtful Accounts</u>

Accounts                                          Debit       Credit

Jan. 1 Beginning balance                             $53,800

Jan. 19 Accounts Receivable                           2,560

Apr. 3 Accounts Receivable       $14,670

July 16 Accounts Receivable        19,725

Nov. 23 Accounts Receivable                         4,175

Dec. 31 Accounts Receivable       25,110

Dec. 31 Ending balance           $40,100

Dec. 31 Bad Debts Expenses                  $39,070

Totals                                        $99,605   $99,605

4. a. Bad Debt Expense for the year = $39,070

4.b. Balance for Allowance Accounts = $40,100

4.c. Expected net realizable value of the accounts receivable = $1,259,400 ($1,299,500 - $40,100)

Data Analysis:

Jan. 19 Accounts Receivable $2,560 Allowance for Uncollectible Accounts $2,560

Jan. 19 Cash $2,560 Accounts Receivable $2,560

Apr. 3 Allowance for Uncollectible Accounts $14,670 Accounts Receivable $14,670

July 16 Cash $6,575 Allowance for Uncollectible Accounts $19,725 Accounts Receivable $26,300

Nov. 23 Accounts Receivable $4,175 Allowance for Uncollectible Accounts $4,175

Nov. 23 Cash $4,175 Accounts Receivable $4,175

Dec. 31 Allowance for Uncollectible Accounts $25,110 Accounts Receivable $25,110

Accounts Receivable ending balance = $1,299,500

Allowance for Uncollectible Accounts ending balance = $56,500

Learn more: brainly.com/question/22984282

4 0
2 years ago
342,802 to the nearest hundred thousands
Maksim231197 [3]
1. The number 3 is located in the hundred thousands place.

2. Since the number 4 is located in the ten thousands place, it's telling 3 to stay the same 

Stays the Same: 1,2,3,4
Goes Up: 5,6,7,8, etc...

342,802 ⇒ 300,000
3 0
3 years ago
Read 2 more answers
Look at the system of equations below.
Paul [167]

Answer:

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=2,\:y=-1

Step-by-step explanation:

Considering the system of the equation

\begin{bmatrix}y=-2x+3\\ 4x-3y=11\end{bmatrix}

\mathrm{Subsititute\:}y=-2x+3

\begin{bmatrix}4x-3\left(-2x+3\right)=11\end{bmatrix}

\mathrm{Isolate}\:x\:\mathrm{for}\:4x-3\left(-2x+3\right)=11

4x-3\left(-2x+3\right)=11

4x+6x-9=11

10x-9=11

10x-9+9=11+9

10x=20

x=2

\mathrm{For\:}y=-2x+3

\mathrm{Subsititute\:}x=2

y=-2\cdot \:2+3

y=-1

\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}

x=2,\:y=-1

7 0
3 years ago
Solve n3 + 2n2 - 15n = 0 by factoring.
azamat
N³ - 2n² - 15n = 0

"n" 

n (n² + 2n - 15) = 0

n = 0

n² + 2n - 15 = 0

Δ = (2)² - 4(1)(-15)
Δ = 4 + 60 = 64

n' = (-2+8) / 2 = 6/2 =3
n'' = (-2-8) / 2 = -10/2 = -5

Solution:

S {-5 , 0 , 3 }
5 0
3 years ago
Read 2 more answers
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