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adelina 88 [10]
4 years ago
11

Water is being split to form two new substances hydrogen and oxygen is this a change of state?

Physics
1 answer:
Stella [2.4K]4 years ago
5 0

I'd say you haven't given us enough information to answer that.

When we talk about "change of state", we're talking about changes
between solid, liquid, and gas.

Tell us what the state of the water is, and what the states of the
hydrogen and oxygen are after the split, and we'll be able to
summarize the changes of state that may be taking place. 

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Give an example of a situation when it would be appropriate to round a number and a situation in which it would not be appropria
anzhelika [568]
A number might be rounded when determining the number of people who will attend a basketball game. A number should not be rounded when determining the number of students who will participate in a chemistry lab. Only an estimate is needed for attendance at a basketball game because everyone will still get to see the game. In a chemistry lab the correct number of students should be known so that everybody has the proper equipment to use.
8 0
3 years ago
You start at (8, 1). You move right 2 units. Where do you end?
ivann1987 [24]

I'm pretty sure should be shifting your transformation those two units to the right from the original function.

Moving right = subtracting

Moving left = adding

4 0
3 years ago
An aircraft is at a standstill. It accelerates to 140kts in 28 seconds. The aircraft weighs 28,000 lbs. How many feet of runway
stiv31 [10]

Answer:

runway use is 3307.8 feet

Explanation:

given data

velocity = 140 kts = 140 × 0.5144 m/s = 72.016 m/s

time = 28 seconds

weight = 28000 lbs

to find out

How many feet of runway was used

solution

we will use here first equation of motion for find acceleration

v = u + at     ..............1

here v is velocity given and u is initial velocity that is 0 and a is acceleration and t is time

put here value in equation 1

72.016 = 0 + a(28)

a = 2.572 m/s²

and

now apply third equation of motion

s = ut + 0.5×a×t²    .......................2

here s is distance and u is initial speed and t is time and a is acceleration

put here all value in equation 2

s = 0 + 0.5×2.572×28²  

s = 1008.24 m = 3307.8 ft

so  runway use is 3307.8 feet

5 0
4 years ago
A pressure vessel that has a volume of 10m3 is used to store high-pressure air for operating a supersonic wind tunnel. If the ai
Anna71 [15]

Answer:

The mass of air stored in the vessel is 235.34 kilograms.

Explanation:

Let supossed that air inside pressure vessel is an ideal gas, The density of the air (\rho), measured in kilograms per cubic meter, is defined by following equation:

\rho = \frac{P\cdot M}{R_{u}\cdot T} (1)

Where:

P - Pressure, measured in kilopascals.

M - Molar mass, measured in kilomoles per kilogram.

R_{u} - Ideal gas constant, measured in kilopascal-cubic meters per kilomole-Kelvin.

T - Temperature, measured in Kelvin.

If we know that P = 2026.5\,kPa, M = 28.965\,\frac{kg}{kmol}, R_{u} = 8.314\,\frac{kPa\cdot m^{2}}{kmol\cdot K} and T = 300\,K, then the density of air is:

\rho = \frac{(2026.5\,kPa)\cdot \left(28.965\,\frac{kg}{kmol} \right)}{\left(8.314\,\frac{kPa\cdot m^{2}}{kmol\cdot K} \right)\cdot (300\,K)}

\rho = 23.534\,\frac{kg}{m^{3}}

The mass of air stored in the vessel is derived from definition of density. That is:

m = \rho \cdot V (2)

Where m is the mass, measured in kilograms.

If we know that \rho = 23.534\,\frac{kg}{m^{3}} and V = 10\,m^{3}, then the mass of air stored in the vessel is:

m = \left(23.534\,\frac{kg}{m^{3}} \right)\cdot (10\,m^{3})

m = 235.34\,kg

The mass of air stored in the vessel is 235.34 kilograms.

7 0
3 years ago
what is the electrical current in the conductor if it is connected to a voltage of 75V, with a current of 1A flowing through the
MakcuM [25]

Answer:

75

Explanation:

V=IR

V=75

I=1

So

75=1R. Divide both side by 1

R=75

5 0
3 years ago
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