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svet-max [94.6K]
3 years ago
13

A dry cell does 7.5 j of work through chemical energy transfer 5.00C between terminals of the cell . What is the electric potent

ial between the two terminals?
Physics
1 answer:
lisov135 [29]3 years ago
7 0
Here's a useful factoid that you don't hear about very often:

1 volt means 1 Joule per Coulomb.

When 1 coulomb of charge falls or gets lifted through 1 volt potential difference, it gains or loses 1 Joule of energy.

If you want to lift 5 coulombs to a height of 1 volt, you have to give it 5 joules.

If you actually give those 5 coulombs 7.5 joules instead, they'll rise up to 1.5 volts above the potential where they started. The flowed through a potential DIFFERENCE of 1.5 volts.

(If they started at a point that's connected to the Earth, like a water pipe or a metal flagpole, then their new potential is 1.5 volts, because we define zero as the potential of the ground.)
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A student is walking at a constant speed of 5 km/h. A car passes the student
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3 years ago
You have a spring-loaded air rifle. When it is loaded, the spring is compressed 0.3 m and has a spring constant of 150 N/m. In j
Feliz [49]

The potential energy of the spring is 6.75 J

The elastic potential energy stored in the spring is given by the equation:

E= \frac{1}{2} kx^2

where;

k is the spring constant

x is the compression/stretching of the string

In this problem, we have the spring as follows:

k = 150 N/m is the spring constant

x = 0.3 m is the compression

Substituting in the equation, we get

E=\frac{1}{2} (150) (0.3)^2

E=6.75J

Therefore. the elastic potential energy stored in the spring is 6.75J .

Learn more about potential energy here:

brainly.com/question/10770261

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2 years ago
The mass of the motorbike and rider is 286 kg. Calculate the acceleration of the motorbike at this moment in time.
Aleks04 [339]

Answer:

a=4.03\ m/s^2

Explanation:

Given that,

The mass of the motorbike and rider is 286 kg.

We need to find the acceleration of the motorbike at this moment in time.

Net force acting on the bike is given by :

F = 2000 N - 845 N = 1155 N

Let a be the acceleration of the motorbike. So,

a=\dfrac{F}{m}\\\\a=\dfrac{1155}{286}\\\\a=4.03\ m/s^2

So, the acceleration of the motorbike is 4.03\ m/s^2.

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a turtle swimming in a straight line toward shore has a speed of 0.50 m/s after 4.0s its speed is 0.80 m/s what is the turtle's
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Answer:

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