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svet-max [94.6K]
3 years ago
13

A dry cell does 7.5 j of work through chemical energy transfer 5.00C between terminals of the cell . What is the electric potent

ial between the two terminals?
Physics
1 answer:
lisov135 [29]3 years ago
7 0
Here's a useful factoid that you don't hear about very often:

1 volt means 1 Joule per Coulomb.

When 1 coulomb of charge falls or gets lifted through 1 volt potential difference, it gains or loses 1 Joule of energy.

If you want to lift 5 coulombs to a height of 1 volt, you have to give it 5 joules.

If you actually give those 5 coulombs 7.5 joules instead, they'll rise up to 1.5 volts above the potential where they started. The flowed through a potential DIFFERENCE of 1.5 volts.

(If they started at a point that's connected to the Earth, like a water pipe or a metal flagpole, then their new potential is 1.5 volts, because we define zero as the potential of the ground.)
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A thin conducting square plate 1.0 m on the side is given a charge of-2.0 x 10-6 c. A proton is placed 1.0 en above the center o
adell [148]

Answer:

Acceleration, a=1.08\times 10^{13}\ m/s^2

Explanation:

It is given that,

Side of the square plate, l = 1 m

Charge on the square plate, Q=-2\times 10^{-6}\ C

Position of a proton, x = 1 cm

The electric field due to a parallel plate is given by :

E=\dfrac{Q}{2A\epsilon_o}

Electric force is given by :

F = q E

F=\dfrac{Qe}{2A\epsilon_o}

e is the charge on electron

The acceleration of the proton can be calculated as :

a=\dfrac{F}{m}

m is the mass of proton

a=\dfrac{Qe}{2A\epsilon_o m}

a=\dfrac{2\times 10^{-6}\times 1.6\times 10^{-19}}{2(1)^2\times 8.85\times 10^{-12}\times {1.67\times 10^{-27}}}

a=1.08\times 10^{13}\ m/s^2

So, the acceleration of the proton is 1.08\times 10^{13}\ m/s^2. Hence, this is the required solution.

3 0
3 years ago
Nuclear fusion combines nuclei to form: lighter elements heavier elements
valkas [14]

Answer:

yes

Explanation:

Nuclear fusion is a reaction in which two or more atomic nuclei are combined to form one or more different atomic nuclei and subatomic particles.

5 0
3 years ago
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When drawing a free body diagram, which of the following things would NOT be included
Neko [114]
C. Mass of the object
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Why is it important we uncover and study fossils?
Ilia_Sergeevich [38]

its important so we can learn things about the species  

4 0
3 years ago
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According to Kepler's Third Law, a solar-system planet that has an orbital radius of 4 AU would have an orbital period of about
NARA [144]

Answer:

Orbital period, T = 1.00074 years

Explanation:

It is given that,

Orbital radius of a solar system planet, r=4\ AU=1.496\times 10^{11}\ m

The orbital period of the planet can be calculated using third law of Kepler's. It is as follows :

T^2=\dfrac{4\pi^2}{GM}r^3

M is the mass of the sun

T^2=\dfrac{4\pi^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times (1.496\times 10^{11})^3    

T^2=\sqrt{9.96\times 10^{14}}\ s

T = 31559467.6761 s

T = 1.00074 years

So, a solar-system planet that has an orbital radius of 4 AU would have an orbital period of about 1.00074 years.

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