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Answer:
Time observed by the astronaut = 2.388 hours
Distance traveled be according to an observer on Earth = 1.27 × 10¹¹ m
Distance traveled according to the astronaut = 2.52 × 10¹² m
Explanation:
Given:
Speed of the astronaut, v = 0.980c
time = 12.0 hr
now, from the time dilation formula we have
here
t' is the time observed by the astronaut
c is the speed of the light = 3 × 10⁸ m/s
thus,
or
t' = 2.388 hours
Now,
Distance = Velocity × time
The distance traveled be according to an observer on Earth will be
Distance = 0.980c × ( 12 × 60 × 60 )
or
D = 0.980 × 3 × 10⁸ × ( 12 × 60 × 60 )
or
Distance = 1.27 × 10¹¹ m
And, The distance traveled according to the astronaut will be
Distance = velocity × t'
or
D = 0.980 × 3 × 10⁸ × ( 2.388 × 60 × 60 )
or
Distance = 2.52 × 10¹² m
I = 6A
V = 94V
According to ohm's law ,
V = IR
R = 94 / 6
R = 15.66 ohm
seldon
Answer:
250+50=300ms-¹
I would appreciate if my answer is chosen as a brainliest answer
Answer:
Explanation:
d = Diameter of typical neutron star = 20 km = 20000 m
D = Distance between Earth and Moon =
Here, so we use small angle approximation
The angular diameter of the neutron star would be from Earth.