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Ivahew [28]
3 years ago
13

Kailee has 4/5 finished of her math

Mathematics
1 answer:
Helen [10]3 years ago
6 0

Answer:

1/5

Step-by-step explanation:

5/5 - 4/5 = 1/5

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4√3 − 5√7 + 2√3 + 6√7
neonofarm [45]

Answer:

\dashrightarrow \: { \tt{4 \sqrt{3}  - 5 \sqrt{7}  + 2 \sqrt{3} + 6 \sqrt{7}  }} \\  \\  \dashrightarrow \: { \tt{(4 - 2) \sqrt{3}  + (6 - 5) \sqrt{7} }} \\  \\  \dashrightarrow \: { \tt{2 \sqrt{3} +  \sqrt{7}  }} \\  \\  \dashrightarrow \: { \tt{ \sqrt{3 \times 4}  +  \sqrt{7} }} \\  \\   \dashrightarrow \: { \tt{ \sqrt{12}  +  \sqrt{7} }}

3 0
3 years ago
Read 2 more answers
(iv) The area of a rectangle with breadth<br>5 cm is 30 sq. cm. Find its length and<br>perimeter.​
Nataly_w [17]

Answer:

Step-by-step explanation:

if the breadth is 5cm, then you divide 30/5 to get your length since it's length times breadth to get the area, so 6cm for the length

and then it's 2b plus 2l to get your perimeter so

2(5)+2(6)=p

10 plus 12 equals p

22 is your perimeter, 6 is your length

3 0
3 years ago
Multiple choice!!!!!!!!!!!!!!!!!!
dolphi86 [110]
By the external angle theorem 

5x = (5x - 30) +  m < RST

m < RST  = 5x - 5x + 30  = 30

 also m < STR = m < SRT = 5x - 30

So as there are 180 degrees in a triangle:-

5x - 30 + 5x - 30 + 30 = 180

10x = 180 +30+30-30 = 210

x = 21 answer
7 0
3 years ago
Read 2 more answers
A market research firm supplies manufacturers with estimates of the retail sales of their products from samples of retail stores
KengaRu [80]

Answer:

The 95% confidence interval for the difference of means is (7.67, 16.33).

The estimate is Md = 12.

The standard error is sM_d = 2.176.

Step-by-step explanation:

We have to calculate a 95% confidence interval for the difference between means.

The sample 1 (this year's sales), of size n1=36 has a mean of 53 and a standard deviation of 12.

The sample 2 (last year's sales), of size n2=49 has a mean of 41 and a standard deviation of 6.

The difference between sample means is Md=12.

M_d=M_1-M_2=53-41=12

The estimated standard error of the difference between means is computed using the formula:

s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{12^2}{36}+\dfrac{6^2}{49}}\\\\\\s_{M_d}=\sqrt{4+0.735}=\sqrt{4.735}=2.176

The degrees of freedom are:

df=n_1+n_2-1=36+49-2=83

The critical t-value for a 95% confidence interval and 83 degrees of fredom is t=1.989.

The margin of error (MOE) can be calculated as:

MOE=t \cdot s_{M_d}=1.989 \cdot 2.176=4.328

Then, the lower and upper bounds of the confidence interval are:

LL=M_d-t \cdot s_{M_d} = 12-4.328=7.67\\\\UL=M_d+t \cdot s_{M_d} = 12+4.328=16.33

The 95% confidence interval for the difference of means is (7.67, 16.33).

7 0
3 years ago
Does some one want to help me out with a couple questions I don’t get.
frosja888 [35]

Answer:

C

Step-by-step explanation:

7 0
3 years ago
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