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frutty [35]
4 years ago
9

Ann has 30% less money than Mary, and Jessica has 70% more than Mary. If the 3 of them have a (added up) total of $102, how much

money does each girl have individually. Only serious answers. Stupid answers will be reported
Mathematics
1 answer:
Roman55 [17]4 years ago
3 0
Let x be the amount of Ann money, y be Jessica's money and z Mary money. 
30% of z equates 0.3*z. 
Ann has 30% less than z so: x = z - 0.3z = 0.7z.
70% of z equates 0.7z. 
"Jessica has 70% more than Mary " we deduce the equation: y =z+0.7z= 1.7z.
Signe the total is $102, we deduce the equation x+y+z = 102. 
x=0.7z and y=1.7z then 0.7z+1.7z+z=102, therefore 3.4z=102 then 
z =102/3.4 = $30.
x=0.7*30= 21 and y=1.7*30=51.

Ann has $21, Mary has $30 and Jessica has $51.
  
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Answer:

\displaystyle \frac{dA}{dt} = 102 \ m^2/day

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<u>Step 1: Define</u>

<u />\displaystyle l = 10 \ meters<u />

<u />\displaystyle \frac{dl}{dt} = 4 \ m/day<u />

<u />\displaystyle w = 23 \ meters<u />

<u />\displaystyle \frac{dw}{dt} = 1 \ m/day<u />

<u />

<u>Step 2: Differentiate</u>

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<u>Step 3: Solve</u>

  1. [Rate] Substitute in variables [Derivative]:                                                    \displaystyle \frac{dA}{dt} = (10 \ m)(1 \ m/day) + (23 \ m)(4 \ m/day)
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  3. [Rate] Add:                                                                                                      \displaystyle \frac{dA}{dt} = 102 \ m^2/day

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Implicit Differentiation

Book: College Calculus 10e

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