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Dennis_Churaev [7]
3 years ago
15

Suppose that Y and Z are points on the number line.

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
6 0

Answer:

16-17 is the answer

although I am not sure

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Solve the inequality: PLS SHOW YOUR WORK PLEASE<br><br> -45 &lt; 5(p-2)
andrezito [222]

Step-by-step explanation:

Given

-45 < 5(p-2)

Dividing both sides by 5

9 < p - 2

Adding two on both sides

9 + 2 < p - 2 + 2

11 < p

or

p > 11

Hope it will help :)❤

3 0
3 years ago
The scatter plot compares the number of movie tickets sold at a theater daily for 7 days. Which is a reasonable conclusion based
g100num [7]

Answer: D

Step-by-step explanation:

6 0
3 years ago
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Need help fast, please
Eduardwww [97]

Answer:

i need to guess that it be inverse and probably a.

Step-by-step explanation:

3 0
3 years ago
If GF is a midsegment of CDE, find CD.<br><br> A. 3.4<br><br>B. 6.8 <br><br>C. 13.6 <br><br>D. 14
bogdanovich [222]

Answer:

C


Step-by-step explanation:

Triangle CGF and triangle CED are similar. Hence, the ratio of their corresponding sides are equal. Thus we can write:

\frac{5x+4}{2x+3}=\frac{CD}{3x+0.8}

<em>We can now cross multiply and solve for CD:</em>

\frac{5x+4}{2x+3}=\frac{CD}{3x+0.8}\\(5x+4)(3x+0.8)=(2x+3)(CD)\\15x^2+4x+12x+3.2=(2x+3)(CD)\\15x^2+16x+3.2=(2x+3)(CD)\\CD=\frac{15x^2+16x+3.2}{2x+3}

Since GF is a midsegment of CDE, CD is double of CF. So we can write:

CD=2CF\\\frac{15x^2+16x+3.2}{2x+3}=2(3x+0.8)\\\frac{15x^2+16x+3.2}{2x+3}=6x+1.6\\15x^2+16x+3.2=(6x+1.6)(2x+3)\\15x^2+16x+3.2=12x^2+18x+3.2x+4.8\\15x^2+16x+3.2=12x^2+21.2x+4.8\\3x^2-5.2x-1.6=0

<em>By using quadratic formula \frac{-b+-\sqrt{b^2-4ac} }{2a} and with a=3, b= -5.2, and c= -1.6, we find the value of x to be:</em>

\frac{5.2+-\sqrt{(-5.2)^2-4(3)(-1.6)} }{2(3)}=2


<em>Since the expression for CD is \frac{15x^2+16x+3.2}{2x+3} , we plug in x=2 into this expression to find value of CD:</em>

\frac{15(2)^2+16(2)+3.2}{2(2)+3}=13.6

The correct answer is C

6 0
3 years ago
Read 2 more answers
How do i answer this?? please help...
Kipish [7]

The equation cannot be solved, but it can be simplified.

You can't add variables with different exponents. For example, you can't add

x^2  with  x^3  because they have different exponents

7 0
3 years ago
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