<h2>Greetings!</h2><h3>First when doing an inequality, if you find it easier to think of the ≤ signs as equal signs it can make it look easier. </h3>
14 = 2t + 18 = 20
<h3>Because we need to isolate the t, we need to subtract 18 from either side:</h3>
14 - 18 ≤ 2t + 18 - 18 < 20 - 18
<h3>Which then simplifies to:</h3>
-4 ≤ 2t < 2
<h3>Now, to get the t without two lots of it, we simply divide all sides by two:</h3>
-2 ≤ t < 1
<h3>So this means that t is smaller than one and bigger than or equal to -2, and the graph that shows that is C, because it includes -2 but is less than 1.</h3>
<h2>Hope this helps!</h2>
The coefficient would be 1
before every variable, there is a one
So, x is equal to 1x
x+x is 2x
hope this helps:)
Answer: There are no real roots.
Step-by-step explanation:
To find the roots of the function
f(x) = (2^x − 1) - (x2 + 2x − 3) with x ∈ R.
First open the bracket
2^x - 1 - x^2 - 2x + 3 = 0
Rearrange and collect the like terms
2x^2 - x^2 - 2x + 3 - 1= 0
X^2 - 2x + 2 = 0
Factorizing the above equation will be impossible, we can therefore find the root by using completing the square method or the quadratic formula.
X^2 - 2x = - 2
Half of coefficient of x is 1
X^2 - 2x + 1^2 = -2 + 1^2
( x - 1 )^2 = - 1
( x - 1 ) = +/- sqrt(-1)
X = -1 + sqrt (-1) or -1 - sqrt (-1)
The root of the function is therefore
X = -1 + sqrt (-1) or -1 - sqrt (-1)
Since b^2 - 4ac of the function is less than zero, we can therefore conclude that there is no real roots
The values of <span> f(-2), f(-0.5), and f(3) can be solved by substituting the values inside the parentheses to the function to the variable x. We do as follows:
</span><span>1. f(x)=-x+4
</span>f(-2) =-x+4 = 2+4 = 6
f(-0.5) =-x+4 = 0.5 + 4 = 4.5
f(3) =-x+4 = -3+4 = 1<span>
2. f(x)= 3/8x-3
</span>f(-2)= 3/8x-3 = -15/4<span>
f(-0.5) </span>= 3/8x-3 = -51/16<span>
f(3) </span>= 3/8x-3 = -15/8
Hope these answers the question.
Answer:
y = -2/3x + 5/3
Step-by-step explanation:
y = -2/3 x + b
3 = -2/3 (-2) + b
3 = 4/3 + b
5/3 = b
Hope this helps <3
