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valina [46]
4 years ago
6

[50 POINTS!!!] HELP! Solve This Logarithm. Find X. Please Type Steps!

Mathematics
2 answers:
Verdich [7]4 years ago
7 0

Answer:

<h2>x = 15</h2>

Step-by-step explanation:

\text{Domain:}\ x>0\\\\\log_83+\dfrac{1}{2}\log_825=\log_8x\qquad\text{use}\ n\log_ab=\log_ab^n\\\\\log_83+\log_825^\frac{1}{2}=\log_8x\qquad\text{use}\ a^\frac{1}{2}=\sqrt{a}\\\\\log_83+\log_8\sqrt{25}=\log_8x\\\\\log_83+\log_85=\log_8x\qquad\text{use}\ \log_ab+\log_ac=\log_a(bc)\\\\\log_8(3\cdot5)=\log_8x\\\\\log_815=\log_8x\iff15=x\to x=15\in D

gogolik [260]4 years ago
3 0

Answer:

Your answer would be x = 15

I hope his helped and have a wonderful day!

~Real

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Step-by-step explanation:

u should:

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and another one is:

2u + t + 13 = 10t + u - 44» 2u + 8 + 13 = 80 + u - 44»

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8 0
3 years ago
In one year , Melinda’s parents spend 2,440.90 on cable and internet service . If they spend the same amount each month , estima
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Answer:

The monthly fee for cable and internet is 200.

Step-by-step explanation:

Given:

Amount spend on one year for cable and internet service is 2440.90.

Now, to get the monthly fee for same amount spend on a year, by dividing the amount spend on a year with 12. As in one year there are 12 months.

So, 2440.90\div 12

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Therefore, the monthly fee for cable and internet is 200.

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3 years ago
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4 years ago
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3 years ago
The product of two consecutive positive integers is 1111 more than their sum. find the integers.
Alex787 [66]
The correct question is
<span>The product of two consecutive positive integers is 11 more than their sum. find the integers.

Let
x-------> the first </span>positive integer
x+1-----> the second consecutive positive integer

we know that
x*(x+1)=11+(x+(x+1))----> x²+x=11+(2x+1)----> x²+x=2x+12
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using a graph tool------> to resolve the second order equation
see the attached figure

the solution is
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therefore

the numbers are
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the answer is
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5 0
3 years ago
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