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rosijanka [135]
3 years ago
13

What are the opposites of these numbers

Mathematics
1 answer:
MakcuM [25]3 years ago
8 0
Would it be
1) -4.25
2) -5 1/4
3) -1/2
4) -2 1/3
5) 3.85
6) 6.1
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Determine the value of y, if x is –12.<br> y= |x| - 5<br><br> pls quickly
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The answer should be 7
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How can you find 27 + (-40)
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Answer:

27 + (-40) = -13

Step-by-step explanation:

27 + (-40)

= 27 - 40

= -13

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What is the result of (x^2 – 10x) – (–5x^2 + x)?
Tanzania [10]

Answer:

( {x}^{2}  - 10x) - ( - 5 {x}^{2}  + x) \\  {x}^{2}  - 10x + 5 {x}^{2}  - x \\  \boxed{6 {x}^{2}  - 11x}

<h3>(6x²-11x) is the right answer.</h3>
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Why did Martin Luther write the 95 theses?
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Find an m &gt; 0 such that the the equation x^4−(3m+2)x^2+m^2=0 has four real solutions that form an arithmetic sequence.
Aleonysh [2.5K]

Answer:

The value of m is 6.

Step-by-step explanation:

Here, the given equation,

x^4-(3m+2)x^2+m^2=0

x^4+0x^3-(3m+2)x^2+0x+m^2=0

Let the roots of the equation are a-3b, a-b, a+b and a + 3b, ( they must be form an AP )

Thus, we can write,

a-3b+a-b+a+b+a+3b=\frac{\text{coefficient of }x^3}{\text{coefficient of }x^4}

=\frac{0}{1}=0

\implies a=0----(1)

(-3b)(-b)+(-b)(b)+(b)(3b)+(3b)(-3b)+(-b)(3b)+(-3b)(b)=\frac{\text{coefficient of }x^2}{\text{coefficient of }x^4}}

=\frac{-3m-2}{1}

3b^2-b^2+3b^2-9b^2-3b^2-3b^2=-3m-2

-10b^2=-3m-2

\implies b^2=\frac{3m+2}{10}-----(2)

(-3b)(-b)(b)(3b)=\frac{\text{Constant term}}{\text{coefficient of}x^4}= m^2

9b^4=m^2

9(\frac{3m+2}{10})^2=m^2

9(\frac{9m^2+4+12m}{100})=m^2

81m^2+36+108m=100m^2

-19m^2+108m+36=0

19m^2-108m-36=0

19m^2-114m+6m-36=0

19m(m-6)+6(m-6)=0

(19m+6)(m-6)=0

\implies m=-\frac{6}{19}\text{ or }m=6

But m > 0,

Hence, the value of m is 6.

4 0
3 years ago
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