Demonstrate that the digits of a perfect square cannot add to 2, 3, 5, 6, or 8

1 answer:

5 0

It depends on what did you mean by saying perfect square. If I've understood it correctly, I can help you with a part of your problem. The squares of mod 9 are 1,4,7 which are came from 1,2,4. Addition of the given numbers are 2,3,5,6, 8, which are exactly the part of your problem. This number, which is not shown as squares Mod 9, and thus doesn't appear as a sum of digits of a perfect square. I hope you will find it helpful.

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Question 5(A)
Answer:51
Explanation
Step 1:evaluate the power
Step2:add the numbers
Step 3:calculate the square root
Step4:reduce the fraction with 4
Step5:calculate the sum or the difference and ur final answer is 51

Question 5(B)
Answer:9/2
Explanation:
Step 1:calculate the difference
Step 2:evaluate the power
Step 3:subtract the numbers
Step 4:calculate the sum
And ur final answer is 9/2

Question 6:(A)
Answer:x=36/11
Explanation:
Step 1:distribute 4 through the parentheses
Step 2:move variable to the left hand side and change its sign
Step 3:move constant to the right hand side and Change it’s sign
Step 4:collect like items
Step 5:add the numbers
Step 6:divide both sides of the equation by 11
And ur final answer is x=36/11

Question 6(B)
Answer:x=192
Explanation:
Step 1:multiply both sides of the equation by 3
Step 2:move the constant to the right hand side and change its sign
Step 3:add the numbers
And ur final answer is x=192

Question 7
Answer B($60)
Explanation:the shape is rectangular and it is 12 feet long and the other is 5 feet wide it’s like finding the area of it so u basically need to multiply 12 by 5 and ur answer is 60

Here is the answers and the explanations step by step I hope it helps
Have a great day and stay safe

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