Y=ab^x
logab=x
log7(1/343)=-3
y=7(1/343)^-3

- How do you simplify this?
- x²y+xy² / y²+2/5 × xy


Factor the expressions that are not already factored.
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<u>How </u><u>to</u><u> factorise</u><u> </u><u>:</u><u>-</u>
<u>NUMERATOR</u> 

Factor out xy.

<u>DENOMINATOR</u> 

Factor out 1/5.

_____
Continuing...

Cancel out y in both the numerator and denominator.

Expand the expression.

This can further simplified to as 

This is the concept of algebra, to solve the expression we proceed as follows;
cos 2x-cosx=0
cos 2x=cosx
but:
cos 2x+1=2(cos^2x)
thereore;
from:
cos 2x=cos x
adding 1 on both sides we get:
cos 2x+1=cos x+1
2(cos^2x)=cosx+1
suppose;
cos x=a
thus;
2a^2=a+1
a^2-1/2a-1/2=0
solving the above quadratic we get:
a=-0.5 and a=1
when a=-0.5
cosx=-0.5
x=120=2/3π
when x=1
cos x=1
x=0
the answer is:
x=0 or x=2/3π